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Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.
  • a)
    (cos(βψ))
  • b)
    (cosψ)
  • c)
    (cosβ cosψ)
  • d)
    (cosβ cos(βψ)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Phasor diagram of load voltage (V), current in pressure coil ((IP)), ...
P = V cosβ.IC cosψ
P = V IC cosβ cosψ
Pα cosβ cosψ
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Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.a)(cos(βψ))b)(cosψ)c)(cosβ cosψ)d)(cosβ cos(βψ)Correct answer is option 'C'. Can you explain this answer?
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Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.a)(cos(βψ))b)(cosψ)c)(cosβ cosψ)d)(cosβ cos(βψ)Correct answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.a)(cos(βψ))b)(cosψ)c)(cosβ cosψ)d)(cosβ cos(βψ)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.a)(cos(βψ))b)(cosψ)c)(cosβ cosψ)d)(cosβ cos(βψ)Correct answer is option 'C'. Can you explain this answer?.
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