On a 3 phase balanced delta-connected load supplied at 240V.A.C The wattmeter reading are-1710& 3210 what is current? A. 10.86A B. 15.86A C. 30.86 D. 20.86?

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Answer

Watts and 1200 VAR. The power factor of the load is:

To find the power factor, we first need to calculate the apparent power of the load:

Apparent power = √3 × V × I

where √3 = 1.732 (square root of 3), V = 240V (line voltage), and I = current in one phase.

Since the load is delta-connected, the line current is equal to the phase current. Therefore, we can use Ohm's law to find the current:

I = P / (√3 × V)

where P = 1710 W (wattmeter reading).

I = 1710 / (1.732 × 240) = 4.77 A

Now we can calculate the apparent power:

Apparent power = √3 × V × I

= 1.732 × 240 × 4.77

= 1988 VA

The power factor is the ratio of real power (W) to apparent power (VA):

Power factor = W / VA

= 1710 / 1988

= 0.861

Therefore, the power factor of the load is 0.861 or 86.1%.

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