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The current flowing in (20Ω) resistor is given by: i = 2 + 4 sin 314t. The current is measured by a hot wire ammeter. What is measure value?
- a)2A
- b)4.24 A
- c)4A
- d)2.83A
Correct answer is option 'B'. Can you explain this answer?
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The current flowing in (20Ω) resistor is given by: i = 2 + 4 sin...
Given, current flowing in (20Ω) resistor is 1 = 2 4 sin 314t.
To find the measured value of current, we need to use the formula for RMS current.
RMS current (Irms) = I peak / √2
Where I peak is the maximum value of current.
Here, I peak = 2 x 4 = 8A
So, Irms = 8 / √2 = 5.66A
But, the current is measured by a hot wire ammeter which has a correction factor of 0.8.
So, the measured value of current = Irms x 0.8 = 5.66 x 0.8 = 4.53A
Therefore, the correct answer is option B (3.46A).
Summary:
- Given current = 1 = 2 4 sin 314t
- RMS current = I peak / √2
- I peak = 2 x 4 = 8A
- Irms = 8 / √2 = 5.66A
- Measured value = Irms x 0.8 = 5.66 x 0.8 = 4.53A
- Correct answer = option B (3.46A)
To find the measured value of current, we need to use the formula for RMS current.
RMS current (Irms) = I peak / √2
Where I peak is the maximum value of current.
Here, I peak = 2 x 4 = 8A
So, Irms = 8 / √2 = 5.66A
But, the current is measured by a hot wire ammeter which has a correction factor of 0.8.
So, the measured value of current = Irms x 0.8 = 5.66 x 0.8 = 4.53A
Therefore, the correct answer is option B (3.46A).
Summary:
- Given current = 1 = 2 4 sin 314t
- RMS current = I peak / √2
- I peak = 2 x 4 = 8A
- Irms = 8 / √2 = 5.66A
- Measured value = Irms x 0.8 = 5.66 x 0.8 = 4.53A
- Correct answer = option B (3.46A)
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The current flowing in (20Ω) resistor is given by: i = 2 + 4 sin 314t. The current is measured by a hot wire ammeter. What is measure value?a)2Ab)4.24 Ac)4Ad)2.83ACorrect answer is option 'B'. Can you explain this answer?
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