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Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would be
- a)9.80
- b)13.3
- c)14.7
- d)20.0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Water is pumped through a pipeline to a height of 10 m at a rate of 0...
Power = ρQgH
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Where H is a totally effective head.
P = 1000 × 0.1 × 9.81 × (10 + 5) = 14715 W = 14.7 kW
Most Upvoted Answer
Water is pumped through a pipeline to a height of 10 m at a rate of 0...
To determine the pumping power required to pump water through a pipeline, we need to consider the work done against gravity and the losses due to friction. Here's a step-by-step explanation:
1. Work done against gravity:
- The height to which water is pumped is given as 10 m.
- The rate at which water is pumped is given as 0.1 m^3/s.
- The work done against gravity can be calculated using the formula: Work = force × distance.
- The force exerted by the water is equal to its weight, which can be calculated using the formula: Force = mass × acceleration due to gravity.
- The mass of water pumped in one second is equal to its density multiplied by the volume pumped: Mass = density × volume.
- The density of water is approximately 1000 kg/m^3.
- The acceleration due to gravity is 9.8 m/s^2.
- Therefore, the work done against gravity is given by: Work = (density × volume × acceleration due to gravity) × distance.
2. Losses due to friction:
- The losses due to friction are given as 5 m.
- These losses represent the energy dissipated due to friction between the water and the pipeline.
- To account for these losses, we need to add the frictional losses to the height pumped, as the pump needs to provide additional energy to overcome the friction.
3. Total work done:
- The total work done is the sum of the work done against gravity and the losses due to friction.
- Total Work = Work done against gravity + Losses due to friction.
4. Power calculation:
- Power is the rate at which work is done, and it is given by the formula: Power = Work / time.
- The time is given as 1 second.
- Therefore, the pumping power required is given by: Power = Total Work / time.
By plugging in the given values and performing the calculations, we can find the pumping power required.
In this case, the correct answer is option 'C' (14.7 kW) based on the calculations described above.
1. Work done against gravity:
- The height to which water is pumped is given as 10 m.
- The rate at which water is pumped is given as 0.1 m^3/s.
- The work done against gravity can be calculated using the formula: Work = force × distance.
- The force exerted by the water is equal to its weight, which can be calculated using the formula: Force = mass × acceleration due to gravity.
- The mass of water pumped in one second is equal to its density multiplied by the volume pumped: Mass = density × volume.
- The density of water is approximately 1000 kg/m^3.
- The acceleration due to gravity is 9.8 m/s^2.
- Therefore, the work done against gravity is given by: Work = (density × volume × acceleration due to gravity) × distance.
2. Losses due to friction:
- The losses due to friction are given as 5 m.
- These losses represent the energy dissipated due to friction between the water and the pipeline.
- To account for these losses, we need to add the frictional losses to the height pumped, as the pump needs to provide additional energy to overcome the friction.
3. Total work done:
- The total work done is the sum of the work done against gravity and the losses due to friction.
- Total Work = Work done against gravity + Losses due to friction.
4. Power calculation:
- Power is the rate at which work is done, and it is given by the formula: Power = Work / time.
- The time is given as 1 second.
- Therefore, the pumping power required is given by: Power = Total Work / time.
By plugging in the given values and performing the calculations, we can find the pumping power required.
In this case, the correct answer is option 'C' (14.7 kW) based on the calculations described above.
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Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? for SSC 2025 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer?.
Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? for SSC 2025 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer?.
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Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Water is pumped through a pipeline to a height of 10 m at a rate of 0.1 m3/s. If frictional and other losses amount to 5 m, the pumping power required in kW would bea)9.80b)13.3c)14.7d)20.0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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