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X minus 2 is a factor of the polynomial 3 x cube minus 7 x square kx - 16 then the value of case?
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X minus 2 is a factor of the polynomial 3 x cube minus 7 x square kx...
Introduction:
In this problem, we are given a polynomial and a factor of that polynomial. We need to find the value of a constant 'k'.

Given:
- X minus 2 is a factor of the polynomial 3 x cube minus 7 x square kx - 16

To Find:
We need to find the value of 'k'.

Solution:
We know that if (x-a) is a factor of a polynomial, then the polynomial becomes zero when we substitute 'a' in place of 'x'. So, if (x-2) is a factor of the given polynomial, then the polynomial should become zero when we substitute '2' in place of 'x'.

So, we have:
3(2)^3 - 7(2)^2 + k(2) - 16 = 0
24 - 28 + 2k - 16 = 0
2k = 20
k = 10

Therefore, the value of 'k' is 10.

Conclusion:
We have found the value of 'k' by using the fact that (x-a) is a factor of a polynomial if and only if the polynomial becomes zero when we substitute 'a' in place of 'x'.
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X minus 2 is a factor of the polynomial 3 x cube minus 7 x square kx...
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X minus 2 is a factor of the polynomial 3 x cube minus 7 x square kx - 16 then the value of case?
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