If x minus 2 is a factor of polynomial x cube minus 7 x square x - 1...
Solution:Given, x - 2 is a factor of polynomial x³ - 7x² + x - 16.
We need to find the value of k.
Using factor theorem:If (x - a) is a factor of a polynomial, then the polynomial is completely divisible by (x - a). This means that if we substitute the value of 'a' in the polynomial and the result is zero, then (x - a) is a factor of the polynomial.
So, if (x - 2) is a factor of x³ - 7x² + x - 16, then we have:
(x - 2) divides x³ - 7x² + x - 16
Substituting x = 2, we get:
(2)³ - 7(2)² + (2) - 16 = 0
8 - 28 + 2 - 16 = 0
-34 = 0
This is not possible.
So, we can say that x - 2 is not a factor of x³ - 7x² + x - 16.
Using long division method:We can use the long division method to divide x³ - 7x² + x - 16 by x - 2.
Step 1: Write the dividend and divisor.
_________
x - 2 | x³ - 7x² + x - 16
Step 2: Divide the first term of the dividend by the divisor and write the result.
x²
_________
x - 2 | x³ - 7x² + x - 16
Step 3: Multiply the divisor by the quotient obtained in step 2 and write the result below the dividend.
x²
_________
x - 2 | x³ - 7x² + x - 16
x³ - 2x²
Step 4: Subtract the result obtained in step 3 from the dividend and write the result below.
x²
_________
x - 2 | x³ - 7x² + x - 16
x³ - 2x²
_________
-5x² + x
Step 5: Repeat steps 2 to 4 with the new dividend.
x² - 5x
_________
x - 2 | x³ - 7x² + x - 16
x