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The reduced bearing of a line is N87∘W. Its whole circle bearing is
- a)87∘
- b)273∘
- c)93∘
- d)3∘
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The reduced bearing of a line is N87∘W. Its whole circle bearing isa)...
It is in the 4th quadrant to convert it from RB to WCB = 360°-Bearing of line.
View all questions of this test
360°-87° = 273°.
Hence, the correct option is (b).
Most Upvoted Answer
The reduced bearing of a line is N87∘W. Its whole circle bearing isa)...
Given Information:
- The reduced bearing of a line is N87°W.
To Find:
- The whole circle bearing of the line.
Solution:
1. The reduced bearing is given as N87°W. This means that the angle is measured starting from the north direction and then moving towards the west direction.
2. To convert this reduced bearing into a whole circle bearing, we need to add 180° to the reduced bearing if it is a west direction bearing.
3. In this case, the reduced bearing is N87°W, which means it is a west direction bearing.
4. Therefore, we add 180° to 87° to get the whole circle bearing.
- 87° + 180° = 267°.
5. Hence, the whole circle bearing of the line is 267°.
6. The options given are:
a) 87°
b) 273°
c) 93°
d) 3°
7. From the calculation, we can see that the correct answer is option 'B', which is 273°.
- The reduced bearing of a line is N87°W.
To Find:
- The whole circle bearing of the line.
Solution:
1. The reduced bearing is given as N87°W. This means that the angle is measured starting from the north direction and then moving towards the west direction.
2. To convert this reduced bearing into a whole circle bearing, we need to add 180° to the reduced bearing if it is a west direction bearing.
3. In this case, the reduced bearing is N87°W, which means it is a west direction bearing.
4. Therefore, we add 180° to 87° to get the whole circle bearing.
- 87° + 180° = 267°.
5. Hence, the whole circle bearing of the line is 267°.
6. The options given are:
a) 87°
b) 273°
c) 93°
d) 3°
7. From the calculation, we can see that the correct answer is option 'B', which is 273°.
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The reduced bearing of a line is N87∘W. Its whole circle bearing isa)87∘b)273∘c)93∘d)3∘Correct answer is option 'B'. Can you explain this answer?
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