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Deepak walks 20 metres towards the North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position?
- a)20 mts.
- b)60 mts.
- c)50 mts.
- d)30 mts.
Correct answer is option 'B'. Can you explain this answer?
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Deepak walks 20 metres towards the North. He then turns left and walk...
So, Deepak is 60 m far from his original position.
Most Upvoted Answer
Deepak walks 20 metres towards the North. He then turns left and walk...
Given Information:
Deepak walks 20 metres towards the North.
He then turns left and walks 40 metres.
He again turns left and walks 20 metres.
He moves 20 metres after turning to the right.
Explanation:
To solve this problem, we need to track Deepak's movements and determine his final position.
Step 1: Walking towards the North
Deepak walks 20 metres towards the North. This means he moves 20 metres straight ahead in the North direction. We can represent this movement as follows:
North (20)
Step 2: Turning left and walking 40 metres
Deepak turns left after walking towards the North. When he turns left, he will be facing the West direction. He then walks 40 metres in the West direction. We can represent this movement as follows:
North (20) -> West (40)
Step 3: Turning left and walking 20 metres
Deepak turns left again after walking towards the West. When he turns left this time, he will be facing the South direction. He then walks 20 metres in the South direction. We can represent this movement as follows:
North (20) -> West (40) -> South (20)
Step 4: Turning right and walking 20 metres
Deepak turns right after walking towards the South. When he turns right, he will be facing the West direction. He then walks 20 metres in the West direction. We can represent this movement as follows:
North (20) -> West (40) -> South (20) -> West (20)
Final Position:
Now, let's determine Deepak's final position by adding up the distances traveled in each direction.
North: 20 metres
West: 40 + 20 = 60 metres
South: 20 metres
To calculate the distance from the original position, we need to find the net displacement. We can use the Pythagorean theorem to find the net displacement.
Net displacement = √(North^2 + West^2 + South^2)
= √(20^2 + 60^2 + 20^2)
= √(400 + 3600 + 400)
= √4400
≈ 66.33
Therefore, Deepak is approximately 66.33 metres away from his original position.
Answer:
The correct answer is option B) 60 metres.
Deepak walks 20 metres towards the North.
He then turns left and walks 40 metres.
He again turns left and walks 20 metres.
He moves 20 metres after turning to the right.
Explanation:
To solve this problem, we need to track Deepak's movements and determine his final position.
Step 1: Walking towards the North
Deepak walks 20 metres towards the North. This means he moves 20 metres straight ahead in the North direction. We can represent this movement as follows:
North (20)
Step 2: Turning left and walking 40 metres
Deepak turns left after walking towards the North. When he turns left, he will be facing the West direction. He then walks 40 metres in the West direction. We can represent this movement as follows:
North (20) -> West (40)
Step 3: Turning left and walking 20 metres
Deepak turns left again after walking towards the West. When he turns left this time, he will be facing the South direction. He then walks 20 metres in the South direction. We can represent this movement as follows:
North (20) -> West (40) -> South (20)
Step 4: Turning right and walking 20 metres
Deepak turns right after walking towards the South. When he turns right, he will be facing the West direction. He then walks 20 metres in the West direction. We can represent this movement as follows:
North (20) -> West (40) -> South (20) -> West (20)
Final Position:
Now, let's determine Deepak's final position by adding up the distances traveled in each direction.
North: 20 metres
West: 40 + 20 = 60 metres
South: 20 metres
To calculate the distance from the original position, we need to find the net displacement. We can use the Pythagorean theorem to find the net displacement.
Net displacement = √(North^2 + West^2 + South^2)
= √(20^2 + 60^2 + 20^2)
= √(400 + 3600 + 400)
= √4400
≈ 66.33
Therefore, Deepak is approximately 66.33 metres away from his original position.
Answer:
The correct answer is option B) 60 metres.
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Solutions for Deepak walks 20 metres towards the North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position?a)20 mts.b)60 mts.c)50 mts.d)30 mts.Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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