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Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together:
  • a)
    10 (5/11) min. past 8
  • b)
    10 (8/11) min. past 8
  • c)
    10 (10/11) min. past 8
  • d)
    10 (6/11) min. past 8
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Find at what time between 8 and 9 o'clock will the hands of a clock b...
At 8 o'clock, the hour hand is at 8 and the min. hand is at 12, i.e., the two hands are 20 min. spaces apart To be in the same straight line but not together, they will be 30 min. spaces apart. So, the min. hand will have to gain (30−20)=10 min. spaces over the hour hand Now, 55 min. are gained in 60 min 10 min. will be gained in (60/55 ×10) mine 10(10/11) min
∴ The hand will be in the same line but not together at 10(10/11) min. past 8
Hence the correct answer is option A.
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Most Upvoted Answer
Find at what time between 8 and 9 o'clock will the hands of a clock b...
Time at which the hands of a clock will be in the same straight line but not together:

To solve this problem, we need to understand the movement of the hour and minute hands of a clock. The hour hand moves 12 times slower than the minute hand. In one hour, the minute hand completes 360 degrees, while the hour hand only completes 30 degrees.

Approach:

1. Let's assume that the minute hand is at 12 and the hour hand is at some position x minutes past 8.
2. The minute hand covers 360 degrees in 60 minutes, so in x minutes, it covers (360/60) * x degrees.
3. The hour hand covers 30 degrees in 60 minutes, so in x minutes, it covers (30/60) * x degrees.
4. Now, we need to find the angle between the minute and hour hand. If the angle is 180 degrees, it means they are in the same straight line but not together.
5. The angle between the hands of the clock is given by the formula: |(360/12) * x - (360/60) * x|.
6. Simplifying the above equation, we get |(30 * x) - (6 * x)| = |24 * x|.
7. We need to find the value of x between 0 and 60 for which |24 * x| = 180.
8. Solving the equation, we get x = 180/24 = 7.5 minutes.
9. Since we need to find the time between 8 and 9 o'clock, we add 7.5 minutes to 8 o'clock.
10. The time at which the hands of the clock will be in the same straight line but not together is 8:07.5 or 10 (10/11) minutes past 8 o'clock.

Therefore, the correct answer is option 'C' 10 (10/11) min. past 8.
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Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together:a)10 (5/11) min. past 8b)10 (8/11) min. past 8c)10 (10/11) min. past 8d)10 (6/11) min. past 8Correct answer is option 'C'. Can you explain this answer?
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