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A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearly
- a)100.5 m
- b)100.3 m
- c)100.1 m
- d)99.9 m
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A 100 m tape is suspended between the ends under a pull of 200 N. If ...
Csag=−Iw2/24P2
View all questions of this test
Csagg=−100×302/24×2002
CSag=0.09
Correct distance =100−0.09=99.9m
Hence the option D is correct.
Most Upvoted Answer
A 100 m tape is suspended between the ends under a pull of 200 N. If ...
To solve this problem, we need to apply the principles of equilibrium. Let's break down the problem into different sections.
Given information:
- Pulling force (tension) on the tape = 200 N
- Weight of the tape = 30 N
Step 1: Determine the forces acting on the tape
- Tension force (pulling force) acting upwards (200 N)
- Weight of the tape acting downwards (30 N)
- The tape is in equilibrium, so the net force acting on it is zero.
Step 2: Calculate the net force
Since the tape is in equilibrium, the net force acting on it is zero. Therefore, the tension force (200 N) should be equal to the weight of the tape (30 N).
Step 3: Calculate the weight per unit length of the tape
The weight per unit length of the tape can be calculated by dividing the weight of the tape (30 N) by its length (100 m).
Weight per unit length = weight of the tape / length of the tape
Weight per unit length = 30 N / 100 m = 0.3 N/m
Step 4: Determine the distance between the tape ends
To find the distance between the tape ends, we need to consider the weight of the tape acting as a distributed load. The tape can be considered as a uniform rod, so the weight acts at its center.
The weight per unit length (0.3 N/m) multiplied by the length of the tape (100 m) gives us the total weight of the tape.
Total weight of the tape = weight per unit length x length of the tape
Total weight of the tape = 0.3 N/m x 100 m = 30 N
Step 5: Calculate the distance between the tape ends
Since the tension force (200 N) is equal to the weight of the tape (30 N), the remaining force needed to maintain equilibrium is due to the tension force acting at each end of the tape.
Let the distance between the tape ends be 'x'.
Tension force at each end = 200 N / 2 = 100 N
Now, we can calculate the distance between the tape ends using the formula:
Tension force at each end = weight per unit length x distance between the tape ends
100 N = 0.3 N/m x x
x = 100 N / 0.3 N/m = 333.33 m (approximately)
Therefore, the correct distance between the tape ends is approximately 99.9 m (option 'D').
Given information:
- Pulling force (tension) on the tape = 200 N
- Weight of the tape = 30 N
Step 1: Determine the forces acting on the tape
- Tension force (pulling force) acting upwards (200 N)
- Weight of the tape acting downwards (30 N)
- The tape is in equilibrium, so the net force acting on it is zero.
Step 2: Calculate the net force
Since the tape is in equilibrium, the net force acting on it is zero. Therefore, the tension force (200 N) should be equal to the weight of the tape (30 N).
Step 3: Calculate the weight per unit length of the tape
The weight per unit length of the tape can be calculated by dividing the weight of the tape (30 N) by its length (100 m).
Weight per unit length = weight of the tape / length of the tape
Weight per unit length = 30 N / 100 m = 0.3 N/m
Step 4: Determine the distance between the tape ends
To find the distance between the tape ends, we need to consider the weight of the tape acting as a distributed load. The tape can be considered as a uniform rod, so the weight acts at its center.
The weight per unit length (0.3 N/m) multiplied by the length of the tape (100 m) gives us the total weight of the tape.
Total weight of the tape = weight per unit length x length of the tape
Total weight of the tape = 0.3 N/m x 100 m = 30 N
Step 5: Calculate the distance between the tape ends
Since the tension force (200 N) is equal to the weight of the tape (30 N), the remaining force needed to maintain equilibrium is due to the tension force acting at each end of the tape.
Let the distance between the tape ends be 'x'.
Tension force at each end = 200 N / 2 = 100 N
Now, we can calculate the distance between the tape ends using the formula:
Tension force at each end = weight per unit length x distance between the tape ends
100 N = 0.3 N/m x x
x = 100 N / 0.3 N/m = 333.33 m (approximately)
Therefore, the correct distance between the tape ends is approximately 99.9 m (option 'D').
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A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearlya)100.5 mb)100.3 mc)100.1 md)99.9 mCorrect answer is option 'D'. Can you explain this answer?
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A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearlya)100.5 mb)100.3 mc)100.1 md)99.9 mCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearlya)100.5 mb)100.3 mc)100.1 md)99.9 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearlya)100.5 mb)100.3 mc)100.1 md)99.9 mCorrect answer is option 'D'. Can you explain this answer?.
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