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A railway curve of 1350 m radius is to be set out to connect two tangents. If the design speed is 110 kmph and the rate of change of acceleration is 0.3 m/s3, the shift of the circular curve will be nearly
  • a)
    0.18 m
  • b)
    0.15 m
  • c)
    0.14 m
  • d)
    0.12 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A railway curve of 1350 m radius is to be set out to connect two tang...
Length of transition curve, L=v3/cR=(0.278×110)3/(0.3×1350)=70.61m
Shift of curve, S=L2/24R=0.154m
Hence the option B is correct.
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Most Upvoted Answer
A railway curve of 1350 m radius is to be set out to connect two tang...
Given:
- Radius of the railway curve = 1350 m
- Design speed = 110 kmph
- Rate of change of acceleration = 0.3 m/s^3

To find:
The shift of the circular curve

Solution:
The shift of the circular curve can be calculated using the formula:

Shift = (V^2) / (127 * R * a)

Where:
V = Design speed in m/s
R = Radius of the curve
a = Rate of change of acceleration

Step 1: Convert the design speed from km/h to m/s

Given design speed = 110 kmph

1 km = 1000 m
1 hour = 3600 seconds

So, design speed in m/s = (110 * 1000) / 3600 = 30.56 m/s

Step 2: Substitute the given values into the formula

Shift = (30.56^2) / (127 * 1350 * 0.3)

Calculating the above expression, we get:

Shift ≈ 0.150 m

Therefore, the shift of the circular curve is approximately 0.15 m.

Hence, option B is the correct answer.
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A railway curve of 1350 m radius is to be set out to connect two tangents. If the design speed is 110 kmph and the rate of change of acceleration is 0.3 m/s3, the shift of the circular curve will be nearlya)0.18 mb)0.15 mc)0.14 md)0.12 mCorrect answer is option 'B'. Can you explain this answer?
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