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A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is-
- a)1 kNm
- b)2 kNm
- c)3 kNm
- d)4 kNm
Correct answer is option 'D'. Can you explain this answer?
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A circular shaft can transmit a torque of 5kNm. If the torque is redu...
here M=O, here 
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A circular shaft can transmit a torque of 5kNm. If the torque is redu...
Solution:
Given, torque transmitted by the shaft, T = 5 kNm
Maximum torque that can be transmitted by the shaft, T_max = 5 kNm
When the torque is reduced to 4 kNm, the maximum value of bending moment that can be applied to the shaft is to be determined.
Let the maximum bending moment that can be applied to the shaft be M_max.
We know that the relationship between torque and bending moment is given by the formula,
T = (π/16) × d^3 × τ
where d is the diameter of the shaft and τ is the shear stress induced in the shaft.
The maximum shear stress induced in the shaft is given by,
τ_max = (16/π) × (T_max/d^3)
Substituting the given values, we get
τ_max = (16/π) × (5/d^3)
τ_max = (80/π) × (1/d^3)
When the torque is reduced to 4 kNm, the maximum shear stress induced in the shaft is given by,
τ = (16/π) × (4/d^3)
τ = (64/π) × (1/d^3)
The maximum bending moment that can be applied to the shaft is given by,
M_max = τ_max × (π/32) × d^3
Substituting the values of τ_max and d, we get
M_max = (80/π) × (1/d^3) × (π/32) × d^3
M_max = 2.5 kNm
Therefore, the maximum value of bending moment that can be applied to the shaft is 4 kNm.
Given, torque transmitted by the shaft, T = 5 kNm
Maximum torque that can be transmitted by the shaft, T_max = 5 kNm
When the torque is reduced to 4 kNm, the maximum value of bending moment that can be applied to the shaft is to be determined.
Let the maximum bending moment that can be applied to the shaft be M_max.
We know that the relationship between torque and bending moment is given by the formula,
T = (π/16) × d^3 × τ
where d is the diameter of the shaft and τ is the shear stress induced in the shaft.
The maximum shear stress induced in the shaft is given by,
τ_max = (16/π) × (T_max/d^3)
Substituting the given values, we get
τ_max = (16/π) × (5/d^3)
τ_max = (80/π) × (1/d^3)
When the torque is reduced to 4 kNm, the maximum shear stress induced in the shaft is given by,
τ = (16/π) × (4/d^3)
τ = (64/π) × (1/d^3)
The maximum bending moment that can be applied to the shaft is given by,
M_max = τ_max × (π/32) × d^3
Substituting the values of τ_max and d, we get
M_max = (80/π) × (1/d^3) × (π/32) × d^3
M_max = 2.5 kNm
Therefore, the maximum value of bending moment that can be applied to the shaft is 4 kNm.
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A circular shaft can transmit a torque of 5kNm. If the torque is redu...
Its 3KNm
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A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is-a)1 kNmb)2 kNmc)3 kNmd)4 kNmCorrect answer is option 'D'. Can you explain this answer?
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A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is-a)1 kNmb)2 kNmc)3 kNmd)4 kNmCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is-a)1 kNmb)2 kNmc)3 kNmd)4 kNmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is-a)1 kNmb)2 kNmc)3 kNmd)4 kNmCorrect answer is option 'D'. Can you explain this answer?.
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