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The probability of getting exactly one head in tossing a pair of coins is
(a) 0
(b) 1
(c) 1/3
(d)1/2?
(a) 0
(b) 1
(c) 1/3
(d)1/2?
Most Upvoted Answer
The probability of getting exactly one head in tossing a pair of coins...
Understanding the problem:
We need to find the probability of getting exactly one head when tossing a pair of coins. In this situation, we have two possible outcomes for each coin toss - either a head or a tail.
Approach:
To solve this problem, we can use the concept of probability. The probability of an event occurring is defined as the number of favorable outcomes divided by the total number of possible outcomes.
Solution:
Let's consider the possible outcomes when tossing a pair of coins:
- Head-Head (HH)
- Head-Tail (HT)
- Tail-Head (TH)
- Tail-Tail (TT)
From these four possible outcomes, we can see that there are three outcomes where we can get exactly one head (HT, TH, TT).
Therefore, the number of favorable outcomes is 3, and the total number of possible outcomes is 4.
Calculating probability:
The probability of getting exactly one head can be calculated as:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
Plugging in the values, we get:
Probability = 3 / 4
Simplifying the fraction, we have:
Probability = 3/4 = 0.75
Therefore, the probability of getting exactly one head when tossing a pair of coins is 0.75.
Answer:
The correct option is (a) 0
We need to find the probability of getting exactly one head when tossing a pair of coins. In this situation, we have two possible outcomes for each coin toss - either a head or a tail.
Approach:
To solve this problem, we can use the concept of probability. The probability of an event occurring is defined as the number of favorable outcomes divided by the total number of possible outcomes.
Solution:
Let's consider the possible outcomes when tossing a pair of coins:
- Head-Head (HH)
- Head-Tail (HT)
- Tail-Head (TH)
- Tail-Tail (TT)
From these four possible outcomes, we can see that there are three outcomes where we can get exactly one head (HT, TH, TT).
Therefore, the number of favorable outcomes is 3, and the total number of possible outcomes is 4.
Calculating probability:
The probability of getting exactly one head can be calculated as:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
Plugging in the values, we get:
Probability = 3 / 4
Simplifying the fraction, we have:
Probability = 3/4 = 0.75
Therefore, the probability of getting exactly one head when tossing a pair of coins is 0.75.
Answer:
The correct option is (a) 0
Community Answer
The probability of getting exactly one head in tossing a pair of coins...
Answer is D
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The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2?
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The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2?.
The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability of getting exactly one head in tossing a pair of coins is(a) 0(b) 1(c) 1/3(d)1/2?.
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