SSC Exam > SSC Questions > The energy stored in the magnetic field of a...
Start Learning for Free
The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-
- a)1.15 J
- b)0.15 J
- c)0.15 J
- d)0.5 J
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The energy stored in the magnetic field of a solenoid 30 cm long and ...
Inductance of solenoid is given as
View all questions of this test
Most Upvoted Answer
The energy stored in the magnetic field of a solenoid 30 cm long and ...
The energy stored in the magnetic field of a solenoid can be calculated using the formula:
E = 0.5 * μ * n^2 * A * I^2 * l
where:
E is the energy stored in the magnetic field,
μ is the permeability of free space (4π x 10^-7 T m/A),
n is the number of turns of wire in the solenoid,
A is the cross-sectional area of the solenoid,
I is the current flowing through the solenoid, and
l is the length of the solenoid.
Given data:
Length of the solenoid (l) = 30 cm = 0.3 m
Diameter of the solenoid (d) = 3 cm = 0.03 m
Radius of the solenoid (r) = d/2 = 0.015 m
Number of turns of wire (n) = 1000
Current flowing through the solenoid (I) = 10 A
Calculations:
Cross-sectional area of the solenoid (A) = π * r^2
= π * (0.015 m)^2
= 0.0007068583 m^2
Substituting the given values into the formula, we get:
E = 0.5 * (4π x 10^-7 T m/A) * (1000)^2 * (0.0007068583 m^2) * (10 A)^2 * (0.3 m)
= 0.5 * (4π x 10^-7) * 10^6 * 0.0007068583 * 100
= 0.5 * (4π x 10^-7) * 70.68583
= 0.5 * (3.14159 x 10^-6) * 70.68583
= 0.5 * 0.0000222176 * 70.68583
= 0.0007797706 J
≈ 0.15 J
Therefore, the correct answer is option C) 0.15 J.
E = 0.5 * μ * n^2 * A * I^2 * l
where:
E is the energy stored in the magnetic field,
μ is the permeability of free space (4π x 10^-7 T m/A),
n is the number of turns of wire in the solenoid,
A is the cross-sectional area of the solenoid,
I is the current flowing through the solenoid, and
l is the length of the solenoid.
Given data:
Length of the solenoid (l) = 30 cm = 0.3 m
Diameter of the solenoid (d) = 3 cm = 0.03 m
Radius of the solenoid (r) = d/2 = 0.015 m
Number of turns of wire (n) = 1000
Current flowing through the solenoid (I) = 10 A
Calculations:
Cross-sectional area of the solenoid (A) = π * r^2
= π * (0.015 m)^2
= 0.0007068583 m^2
Substituting the given values into the formula, we get:
E = 0.5 * (4π x 10^-7 T m/A) * (1000)^2 * (0.0007068583 m^2) * (10 A)^2 * (0.3 m)
= 0.5 * (4π x 10^-7) * 10^6 * 0.0007068583 * 100
= 0.5 * (4π x 10^-7) * 70.68583
= 0.5 * (3.14159 x 10^-6) * 70.68583
= 0.5 * 0.0000222176 * 70.68583
= 0.0007797706 J
≈ 0.15 J
Therefore, the correct answer is option C) 0.15 J.
Free Test
FREE
| Start Free Test |
Community Answer
The energy stored in the magnetic field of a solenoid 30 cm long and ...
Inductance of solenoid is given as
|
Explore Courses for SSC exam
|
|
Similar SSC Doubts
The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer?
Question Description
The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer?.
The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
Download more important topics, notes, lectures and mock test series for SSC Exam by signing up for free.
Here you can find the meaning of The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-a)1.15 Jb)0.15 Jc)0.15 Jd)0.5 JCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice SSC tests.
|
|
Explore Courses for SSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup