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8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13?
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8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solutio...
Solution:
The given solution contains NaOH and H2SO4. NaOH is a strong base and H2SO4 is a strong acid. When NaOH and H2SO4 react, they undergo neutralization reaction and form Na2SO4 and water.
NaOH + H2SO4 → Na2SO4 + H2O
Molar mass of NaOH = 40 g/mol
Molar mass of H2SO4 = 98 g/mol
Number of moles of NaOH = 8 g / 40 g/mol = 0.2 mol
Number of moles of H2SO4 = 4.9 g / 98 g/mol = 0.05 mol
The balanced chemical equation for the reaction between NaOH and H2SO4 shows that 1 mole of NaOH reacts with 1 mole of H2SO4. Therefore, the limiting reactant is H2SO4.
Hence, the number of moles of H2SO4 that react with NaOH is 0.05 mol.
After the reaction, the remaining H2SO4 is 0.05 mol, and the amount of NaOH that is not neutralized is:
0.2 mol - 0.05 mol = 0.15 mol
The concentration of NaOH in the solution is:
0.15 mol / 1 L = 0.15 M
pH of the solution can be calculated as follows:
pH = 14 - pOH
pOH can be calculated using the equation for the concentration of hydroxide ions in a solution of a strong base:
[OH-] = 0.15 M
pOH = -log[OH-] = -log(0.15) = 0.823
pH = 14 - pOH = 14 - 0.823 = 13.177
Therefore, the pH of the solution is 13 (option 4).
Explanation:
The given solution contains NaOH and H2SO4, which react with each other to form Na2SO4 and water. The concentration of NaOH in the solution is calculated using the number of moles of NaOH present in 1 liter of the solution. The pH of the solution is then calculated using the concentration of hydroxide ions in the solution of strong base. The final pH of the solution is 13.
The given solution contains NaOH and H2SO4. NaOH is a strong base and H2SO4 is a strong acid. When NaOH and H2SO4 react, they undergo neutralization reaction and form Na2SO4 and water.
NaOH + H2SO4 → Na2SO4 + H2O
Molar mass of NaOH = 40 g/mol
Molar mass of H2SO4 = 98 g/mol
Number of moles of NaOH = 8 g / 40 g/mol = 0.2 mol
Number of moles of H2SO4 = 4.9 g / 98 g/mol = 0.05 mol
The balanced chemical equation for the reaction between NaOH and H2SO4 shows that 1 mole of NaOH reacts with 1 mole of H2SO4. Therefore, the limiting reactant is H2SO4.
Hence, the number of moles of H2SO4 that react with NaOH is 0.05 mol.
After the reaction, the remaining H2SO4 is 0.05 mol, and the amount of NaOH that is not neutralized is:
0.2 mol - 0.05 mol = 0.15 mol
The concentration of NaOH in the solution is:
0.15 mol / 1 L = 0.15 M
pH of the solution can be calculated as follows:
pH = 14 - pOH
pOH can be calculated using the equation for the concentration of hydroxide ions in a solution of a strong base:
[OH-] = 0.15 M
pOH = -log[OH-] = -log(0.15) = 0.823
pH = 14 - pOH = 14 - 0.823 = 13.177
Therefore, the pH of the solution is 13 (option 4).
Explanation:
The given solution contains NaOH and H2SO4, which react with each other to form Na2SO4 and water. The concentration of NaOH in the solution is calculated using the number of moles of NaOH present in 1 liter of the solution. The pH of the solution is then calculated using the concentration of hydroxide ions in the solution of strong base. The final pH of the solution is 13.
Community Answer
8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solutio...
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8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13?
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8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13?.
8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 8 gram NaOH and 4.9 gram H2SO4 are present in one litre of the solution. What is its pH (1) 1 (2) 2 (3) 12 (4) 13?.
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