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For the circuit shown below ,the black box contains resistors and independent sources only.The current I is 3A and1.5A for R=0 and 2ohm,respectively.for R=1ohm.what is the current?
Most Upvoted Answer
For the circuit shown below ,the black box contains resistors and inde...
Analysis of the Circuit:
To find the current through the circuit when R = 1 ohm, we need to analyze the circuit step by step.
Step 1: Analyzing the Circuit for R = 0 ohm
When R = 0 ohm, the circuit becomes a short circuit. Therefore, the current I will flow through the short circuit.
Step 2: Analyzing the Circuit for R = 2 ohms
When R = 2 ohms, the circuit becomes:
+--------+--------+
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3V 2Ω 1Ω
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+--------+--------+
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+--------+--------+
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+--------+--------+
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+--------+--------+
Using Kirchhoff's laws, we can apply the voltage division rule to find the voltage across the 2-ohm resistor.
V(2Ω) = (2Ω / (2Ω + 1Ω)) * 3V = 2V
Now, using Ohm's law, we can find the current through the 2-ohm resistor.
I(2Ω) = V(2Ω) / 2Ω = 2V / 2Ω = 1A
Step 3: Analyzing the Circuit for R = 1 ohm
When R = 1 ohm, the circuit becomes:
+--------+--------+
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3V 2Ω 1Ω
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
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+--------+--------+
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+--------+--------+
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+--------+--------+
Using Kirchhoff's laws, we can apply the current division rule to find the current through the 1-ohm resistor.
I(1Ω) = (1Ω / (2Ω + 1Ω)) * 1A = 0.33A
Final Answer:
Therefore, when R = 1 ohm, the current through the circuit is 0.33A.
Note:
- The circuit analysis is based on the given information and assumptions made about the circuit elements
To find the current through the circuit when R = 1 ohm, we need to analyze the circuit step by step.
Step 1: Analyzing the Circuit for R = 0 ohm
When R = 0 ohm, the circuit becomes a short circuit. Therefore, the current I will flow through the short circuit.
Step 2: Analyzing the Circuit for R = 2 ohms
When R = 2 ohms, the circuit becomes:
+--------+--------+
| | |
3V 2Ω 1Ω
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
Using Kirchhoff's laws, we can apply the voltage division rule to find the voltage across the 2-ohm resistor.
V(2Ω) = (2Ω / (2Ω + 1Ω)) * 3V = 2V
Now, using Ohm's law, we can find the current through the 2-ohm resistor.
I(2Ω) = V(2Ω) / 2Ω = 2V / 2Ω = 1A
Step 3: Analyzing the Circuit for R = 1 ohm
When R = 1 ohm, the circuit becomes:
+--------+--------+
| | |
3V 2Ω 1Ω
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
| | |
| | |
| | |
| | |
| | |
| | |
+--------+--------+
Using Kirchhoff's laws, we can apply the current division rule to find the current through the 1-ohm resistor.
I(1Ω) = (1Ω / (2Ω + 1Ω)) * 1A = 0.33A
Final Answer:
Therefore, when R = 1 ohm, the current through the circuit is 0.33A.
Note:
- The circuit analysis is based on the given information and assumptions made about the circuit elements
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For the circuit shown below ,the black box contains resistors and independent sources only.The current I is 3A and1.5A for R=0 and 2ohm,respectively.for R=1ohm.what is the current?
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For the circuit shown below ,the black box contains resistors and independent sources only.The current I is 3A and1.5A for R=0 and 2ohm,respectively.for R=1ohm.what is the current? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For the circuit shown below ,the black box contains resistors and independent sources only.The current I is 3A and1.5A for R=0 and 2ohm,respectively.for R=1ohm.what is the current? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the circuit shown below ,the black box contains resistors and independent sources only.The current I is 3A and1.5A for R=0 and 2ohm,respectively.for R=1ohm.what is the current?.
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