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Two DC series motors connected in series draw current I from supply and run at speed N. When the same two-motor are connected in parallel, taking current I from the supply, the speed of each motor will be
  • a)
    (N/2)
  • b)
    N
  • c)
    2N
  • d)
    4N
Correct answer is option 'D'. Can you explain this answer?
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Two DC series motors connected in series draw current I from supply a...
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Two DC series motors connected in series draw current I from supply a...
Solution:

When two DC series motors are connected in series:

- The voltage across each motor is half the supply voltage.
- The current through both motors is the same as the current drawn from the supply.
- The torque output of both motors adds up.
- The speed of both motors is the same, and it is denoted by N.

When the same two motors are connected in parallel:

- The voltage across each motor is the same as the supply voltage.
- The current through each motor is half the current drawn from the supply.
- The torque output of each motor is half of what it was in series connection.
- The speed of each motor increases.

To find the new speed, we can use the following formula:

(N2 / N1) = √(T2 / T1)

Where:

- N1 = Speed of motors in series connection = N
- N2 = Speed of motors in parallel connection (to be determined)
- T1 = Torque output of motors in series connection = T
- T2 = Torque output of motors in parallel connection = T/2 (since torque output is halved in parallel connection)

Substituting the given values, we get:

(N2 / N) = √(T/2T)

(N2 / N) = √(1/2)

N2 = N * √2

Therefore, the speed of each motor when they are connected in parallel is:

N2 = N * √2 = N * 1.414

Since there are two motors in parallel, the total speed of the system is:

Ntotal = N2 * 2 = N * 2.828

Therefore, the correct answer is option D, 4N.
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