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A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?
- a)152.6 N-m
- b)158.6 N-m
- c)166.4 N-m
- d)172.6 N-m
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r...
Since Ish = 220/ 50 = 4.4 A
Ia = 80-4.4 = 75.6 Amp
Eb= V - IaRa
= 220- (75.6 x 0.1) = 212.44
Driving Power Eb.Ia = 212.44x75.6
= 16060 N-m
Output Power = Driving Power - Iron and Friction Losses
= 16060-1600
= 14460 W
Armature Torque
Ta = EbIa/2πN if N in r.p.s
Ta = (60EbIa)/(2πN) if N in r.p.m
so; Ta = (9.55EbIa)/N if N in r.p.s
= (9.55 x 212.44 x 75.6)/800
= 191.7 N-m
Since the whole of armature torque is not available for doing useful work, a certain part is required to overcome iron & friction losses
Hence Lost torque = 9.55x (1600/800)
= 19.1 N-m
Hence Useful Shaft torque = Ta - Tlost
= 191.7 - 19.1
= 172.6 N-m
Ia = 80-4.4 = 75.6 Amp
Eb= V - IaRa
= 220- (75.6 x 0.1) = 212.44
Driving Power Eb.Ia = 212.44x75.6
= 16060 N-m
Output Power = Driving Power - Iron and Friction Losses
= 16060-1600
= 14460 W
Armature Torque
Ta = EbIa/2πN if N in r.p.s
Ta = (60EbIa)/(2πN) if N in r.p.m
so; Ta = (9.55EbIa)/N if N in r.p.s
= (9.55 x 212.44 x 75.6)/800
= 191.7 N-m
Since the whole of armature torque is not available for doing useful work, a certain part is required to overcome iron & friction losses
Hence Lost torque = 9.55x (1600/800)
= 19.1 N-m
Hence Useful Shaft torque = Ta - Tlost
= 191.7 - 19.1
= 172.6 N-m
Most Upvoted Answer
A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r...
Since Ish = 220/ 50 = 4.4 A
Ia = 80-4.4 = 75.6 Amp
Eb= V - IaRa
= 220- (75.6 x 0.1) = 212.44
Driving Power Eb.Ia = 212.44x75.6
= 16060 N-m
Output Power = Driving Power - Iron and Friction Losses
= 16060-1600
= 14460 W
Armature Torque
Ta = EbIa/2πN if N in r.p.s
Ta = (60EbIa)/(2πN) if N in r.p.m
so; Ta = (9.55EbIa)/N if N in r.p.s
= (9.55 x 212.44 x 75.6)/800
= 191.7 N-m
Since the whole of armature torque is not available for doing useful work, a certain part is required to overcome iron & friction losses
Hence Lost torque = 9.55x (1600/800)
= 19.1 N-m
Hence Useful Shaft torque = Ta - Tlost
= 191.7 - 19.1
= 172.6 N-m
Ia = 80-4.4 = 75.6 Amp
Eb= V - IaRa
= 220- (75.6 x 0.1) = 212.44
Driving Power Eb.Ia = 212.44x75.6
= 16060 N-m
Output Power = Driving Power - Iron and Friction Losses
= 16060-1600
= 14460 W
Armature Torque
Ta = EbIa/2πN if N in r.p.s
Ta = (60EbIa)/(2πN) if N in r.p.m
so; Ta = (9.55EbIa)/N if N in r.p.s
= (9.55 x 212.44 x 75.6)/800
= 191.7 N-m
Since the whole of armature torque is not available for doing useful work, a certain part is required to overcome iron & friction losses
Hence Lost torque = 9.55x (1600/800)
= 19.1 N-m
Hence Useful Shaft torque = Ta - Tlost
= 191.7 - 19.1
= 172.6 N-m
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Community Answer
A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r...
Ω and armature resistance is 0.2 Ω. Calculate the following:
1. The armature current
2. The shunt field current
3. The output power of the motor
4. The efficiency of the motor
Solution:
1. The armature current can be calculated using Ohm's law:
Armature current = (Supply voltage - voltage drop across shunt field) / Armature resistance
= (220V - 50Ω x 80A) / 0.2Ω
= 500A
2. The shunt field current can be calculated using Ohm's law:
Shunt field current = voltage drop across shunt field / Shunt field resistance
= 50Ω x 80A
= 4000A
3. The output power of the motor can be calculated using the formula:
Output power = (Armature current x Supply voltage) - (Armature current^2 x Armature resistance)
= (500A x 220V) - (500A^2 x 0.2Ω)
= 110000W or 110 kW
4. The efficiency of the motor can be calculated using the formula:
Efficiency = Output power / Input power
Input power = Supply voltage x Total current
= 220V x 80A
= 17600W or 17.6 kW
Efficiency = 110 kW / 17.6 kW
= 6.25 or 625% (This value is not possible as efficiency cannot be more than 100%. There might be an error in the calculations or in the given values.)
1. The armature current
2. The shunt field current
3. The output power of the motor
4. The efficiency of the motor
Solution:
1. The armature current can be calculated using Ohm's law:
Armature current = (Supply voltage - voltage drop across shunt field) / Armature resistance
= (220V - 50Ω x 80A) / 0.2Ω
= 500A
2. The shunt field current can be calculated using Ohm's law:
Shunt field current = voltage drop across shunt field / Shunt field resistance
= 50Ω x 80A
= 4000A
3. The output power of the motor can be calculated using the formula:
Output power = (Armature current x Supply voltage) - (Armature current^2 x Armature resistance)
= (500A x 220V) - (500A^2 x 0.2Ω)
= 110000W or 110 kW
4. The efficiency of the motor can be calculated using the formula:
Efficiency = Output power / Input power
Input power = Supply voltage x Total current
= 220V x 80A
= 17600W or 17.6 kW
Efficiency = 110 kW / 17.6 kW
= 6.25 or 625% (This value is not possible as efficiency cannot be more than 100%. There might be an error in the calculations or in the given values.)
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A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer?
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A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer?.
A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 220V d.c. shunt motor takes a total current of 80A and runs at 800 r.p.m. The resistance of shunt field is 50Ω and that of armature 0.1Ω The iron and friction losses amount to 1600W. What is the shaft torque?a)152.6 N-mb)158.6 N-mc)166.4 N-md)172.6 N-mCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice SSC tests.
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