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At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:
Mainwinding:R=4Ω:XL=7.5Ω
Starting winding:R=7.5Ω:XL=4Ω
The phase angle between main winding current and starting winding current is
Mainwinding:R=4Ω:XL=7.5Ω
Starting winding:R=7.5Ω:XL=4Ω
The phase angle between main winding current and starting winding current is
- a)34°
- b)47°
- c)12°
- d)23°
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
At starting, the windings of a 230 V. 50 Hz, split-phase induction mot...
Phase angle between V and Im,
ϕm= tan-17.44 = 62∘
Phase angle between V and Is,
ϕs= tan-147.5=28∘
∴ Phase angle between Is and Im,
ϕm= tan-17.44 = 62∘
Phase angle between V and Is,
ϕs= tan-147.5=28∘
∴ Phase angle between Is and Im,
Most Upvoted Answer
At starting, the windings of a 230 V. 50 Hz, split-phase induction mot...
Ω, X=6 ΩAuxiliary winding:R=6 Ω, X=8 ΩThe motor is running at no-load with a current of 2 A in the main winding and 1 A in the auxiliary winding. Determine the power factor of the motor.
To determine the power factor, we can use the concept of the power triangle. The power triangle is a graphical representation of the real power (P), reactive power (Q), and apparent power (S) in an AC circuit.
Apparent power (S) is given by S = V * I, where V is the voltage and I is the current.
For the main winding:
S_main = 230 V * 2 A = 460 VA
For the auxiliary winding:
S_aux = 230 V * 1 A = 230 VA
The total apparent power is the sum of the apparent powers of the main and auxiliary windings:
S_total = S_main + S_aux = 460 VA + 230 VA = 690 VA
The power factor (PF) is the ratio of the real power (P) to the apparent power (S):
PF = P / S
To determine the real power, we need to consider the power dissipated in the resistive components of the windings. The power dissipated in the main winding is given by P_main = I_main^2 * R_main, and the power dissipated in the auxiliary winding is given by P_aux = I_aux^2 * R_aux.
P_main = (2 A)^2 * 4 Ω = 16 W
P_aux = (1 A)^2 * 6 Ω = 6 W
The total real power is the sum of the real powers of the main and auxiliary windings:
P_total = P_main + P_aux = 16 W + 6 W = 22 W
Now we can calculate the power factor:
PF = P_total / S_total
PF = 22 W / 690 VA ≈ 0.0318
Therefore, the power factor of the motor is approximately 0.0318.
To determine the power factor, we can use the concept of the power triangle. The power triangle is a graphical representation of the real power (P), reactive power (Q), and apparent power (S) in an AC circuit.
Apparent power (S) is given by S = V * I, where V is the voltage and I is the current.
For the main winding:
S_main = 230 V * 2 A = 460 VA
For the auxiliary winding:
S_aux = 230 V * 1 A = 230 VA
The total apparent power is the sum of the apparent powers of the main and auxiliary windings:
S_total = S_main + S_aux = 460 VA + 230 VA = 690 VA
The power factor (PF) is the ratio of the real power (P) to the apparent power (S):
PF = P / S
To determine the real power, we need to consider the power dissipated in the resistive components of the windings. The power dissipated in the main winding is given by P_main = I_main^2 * R_main, and the power dissipated in the auxiliary winding is given by P_aux = I_aux^2 * R_aux.
P_main = (2 A)^2 * 4 Ω = 16 W
P_aux = (1 A)^2 * 6 Ω = 6 W
The total real power is the sum of the real powers of the main and auxiliary windings:
P_total = P_main + P_aux = 16 W + 6 W = 22 W
Now we can calculate the power factor:
PF = P_total / S_total
PF = 22 W / 690 VA ≈ 0.0318
Therefore, the power factor of the motor is approximately 0.0318.
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At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer?
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At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer?.
At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer?.
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At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer?, a detailed solution for At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of At starting, the windings of a 230 V. 50 Hz, split-phase induction motor have the following parameters:Mainwinding:R=4Ω:XL=7.5ΩStarting winding:R=7.5Ω:XL=4ΩThe phase angle between main winding current and starting winding current isa)34°b)47°c)12°d)23°Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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