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If resistance is and inductance is 2H in an RL series circuit, the time constant of this circuit will be-
  • a)
    100s
  • b)
    0.001s
  • c)
    0.1s
  • d)
    10s
Correct answer is option 'C'. Can you explain this answer?
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If resistance is and inductance is 2H in an RL series circuit, the ...
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If resistance is and inductance is 2H in an RL series circuit, the ...
The time constant of an RL series circuit can be calculated using the formula:

τ = L/R

where τ is the time constant, L is the inductance, and R is the resistance.

Given that the resistance is and the inductance is 2H, we can substitute these values into the formula to find the time constant.

τ = 2H/ = 1H/

To simplify the expression, we can convert the resistance from kilohms to ohms:

= 1000Ω

Now we can substitute this value into the formula:

τ = 1H/1000Ω

Simplifying further:

τ = 0.001s

So the time constant of the RL series circuit is 0.001 seconds.

Explanation:

- Resistance and Inductance: The question provides the resistance and inductance values for an RL series circuit.
- Time Constant Formula: The time constant of an RL series circuit is given by the formula τ = L/R, where τ is the time constant, L is the inductance, and R is the resistance.
- Substituting Values: We substitute the given resistance and inductance values into the time constant formula. However, the resistance is given in kilohms, so we convert it to ohms by multiplying it by 1000.
- Simplification: We simplify the expression by dividing the inductance value by the resistance value.
- Final Answer: After simplification, we find that the time constant of the RL series circuit is 0.001 seconds.
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If resistance is and inductance is 2H in an RL series circuit, the time constant of this circuit will be-a)100sb)0.001sc)0.1sd)10sCorrect answer is option 'C'. Can you explain this answer?
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