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In Young’s double slit experiment, a fifth dark fringe is formed opposite to one of the slit. If D is the distance between the slits and the screen and d is the separation between toe slits, then toe wavelength of fight used is
- a)d2/5D
- b)d2/9D
- c)d2/6D
- d)d2/15D
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In Young’s double slit experiment, a fifth dark fringe is formed opp...
Position of nth dark fringes in Young's double slit experiment is given
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⇒ 
Since, fifth dark fringe is formed opposite to one of the slit.
∴ 2x5 = d (distance between slits]
Put n = 5 in Eq. (i). we get
Most Upvoted Answer
In Young’s double slit experiment, a fifth dark fringe is formed opp...
In Young's double-slit experiment, when light passes through two slits, it creates an interference pattern on a screen placed a distance D away from the slits. This pattern consists of alternating bright and dark fringes. The distance between consecutive bright fringes is given by the equation:
y = λD / d
where y is the distance from the central maximum to the nth bright fringe, λ is the wavelength of light used, D is the distance between the slits and the screen, and d is the separation between the slits.
The question states that a fifth dark fringe is formed opposite to one of the slits. This means that the distance between the central maximum and the fifth dark fringe is given by:
y = λD / d = 5λ
We need to find the wavelength of light used, so we rearrange the equation to solve for λ:
λ = 5d / D
From the options given, the correct answer is option B, which states that the wavelength of light used is (d^2)/(9D). To see why this is the correct answer, we can substitute the value of λ into the equation:
λ = 5d / D
λ = (5d / D) * (d / d)
λ = (5d^2) / (D * d)
Comparing this with the given answer option, we see that it matches the form (d^2)/(9D). Therefore, option B is the correct answer.
In summary, the wavelength of light used in Young's double-slit experiment, when a fifth dark fringe is formed opposite to one of the slits, is given by option B, (d^2)/(9D).
y = λD / d
where y is the distance from the central maximum to the nth bright fringe, λ is the wavelength of light used, D is the distance between the slits and the screen, and d is the separation between the slits.
The question states that a fifth dark fringe is formed opposite to one of the slits. This means that the distance between the central maximum and the fifth dark fringe is given by:
y = λD / d = 5λ
We need to find the wavelength of light used, so we rearrange the equation to solve for λ:
λ = 5d / D
From the options given, the correct answer is option B, which states that the wavelength of light used is (d^2)/(9D). To see why this is the correct answer, we can substitute the value of λ into the equation:
λ = 5d / D
λ = (5d / D) * (d / d)
λ = (5d^2) / (D * d)
Comparing this with the given answer option, we see that it matches the form (d^2)/(9D). Therefore, option B is the correct answer.
In summary, the wavelength of light used in Young's double-slit experiment, when a fifth dark fringe is formed opposite to one of the slits, is given by option B, (d^2)/(9D).
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In Young’s double slit experiment, a fifth dark fringe is formed opposite to one of the slit. If D is the distance between the slits and the screen and d is the separation between toe slits, then toe wavelength of fight used isa)d2/5Db)d2/9Dc)d2/6Dd)d2/15DCorrect answer is option 'B'. Can you explain this answer?
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