the correct geometry and hybridization for XeF4 is

Question

Answer

Geometry is square pyramidal shape is square planner and hybridization is sp3d2 as XeF4 contain 4 Sigma bond and two lone pair of electron.

Answer

1. Octahedral
2. Square pyramidal
3. Trigonal bipyramidal
4. Square planar
Ans is 1. How?? Why not 4. ?

Answer

it is given geometry only

Answer

so whats d ans

Answer

sp³d²

Answer

ok thank u😊

Answer

Hybridization can be found by formula
1/2[number of valance electrons of central atom+no.of monovalant atoms attached to it+negative charge if any-positive charge if any ]=z
value of z hybridization =2(SP) 3(sp2) 4(sp3) 5(sp3d2) 6(sp3d2)...............

Answer

but

Answer

octahedral is arrangement

Answer

it means i m right the geometry is square planar but in ans it is given octahedral ......

Answer

neet phase 2 question pls reply fast....

Answer

dono sahiii haiii ek tarah arrangement ko hi geometry kah skte hsi

Answer

square planar geometry

Answer

Geometry and Hybridization of XeF4

To determine the correct geometry and hybridization for XeF4 (xenon tetrafluoride), we need to consider the Lewis structure and the concept of hybridization.

Lewis Structure of XeF4
1. Start by determining the total number of valence electrons for the molecule. Xenon (Xe) is in Group 18 of the periodic table and has 8 valence electrons. Each fluorine (F) atom contributes 7 valence electrons. Therefore, the total number of valence electrons is 8 + (4 × 7) = 36.
2. Place the xenon atom in the center, surrounded by the four fluorine atoms.
3. Connect each fluorine atom to the central xenon atom with a single bond, resulting in 4 Xe-F bonds.
4. Distribute the remaining electrons as lone pairs around the fluorine atoms to complete their octets.
5. Place any remaining electrons as lone pairs around the xenon atom.

The resulting Lewis structure for XeF4 is as follows:
```
F
|
F - Xe - F - F
|
F
```

Hybridization of XeF4
Hybridization is a concept used to explain the arrangement of atoms and electron pairs in molecules. It involves the mixing of atomic orbitals to form new hybrid orbitals that are involved in bonding.

In XeF4, the central xenon atom is surrounded by four fluorine atoms. Since xenon is in Group 18, it has an s2p6 electron configuration in its ground state. To form the required number of bonds and achieve the most stable electron arrangement, xenon undergoes sp3d2 hybridization.

Explanation of Hybridization
1. Start with the ground state electron configuration of xenon: [Kr] 5s2 4d10 5p6.
2. Promote one electron from the 5s orbital to the empty 4d orbital, resulting in the electron configuration: [Kr] 5s1 4d10 5p6.
3. The excited xenon atom then combines one 5s, three 5p, and two 4d orbitals to form a set of six sp3d2 hybrid orbitals.
4. These hybrid orbitals are used to form bonds with the four fluorine atoms in a tetrahedral arrangement around the central xenon atom.
5. Each of the six hybrid orbitals overlaps with an atomic orbital from a fluorine atom to form four sigma bonds.
6. The remaining two hybrid orbitals contain lone pairs of electrons.

Summary
XeF4 exhibits an octahedral geometry due to sp3d2 hybridization of the central xenon atom. The xenon atom forms four sigma bonds with the surrounding fluorine atoms, resulting in a tetrahedral arrangement. The remaining two hybrid orbitals contain lone pairs of electrons.

Similar NEET Doubts

The geometry and hybridization of XeF4?

Match the compound given in column I with the hybridization and shape given in column II and markthe correct option.Column-I Column-II(

Ni(nh3)2(cl)2=hybridization geometry and reason for not showing geometrical isomerism?

Geometry nd hybridisation of XeF4?

The complex ion [Co(NH3)6]3+ is formed by sp3d2 hybridisation. Hence the ion should possess

Top Courses for NEETView all

Biology Class 11

Daily Test for NEET Preparation

NEET Mock Test Series 2025

Topic-wise MCQ Tests for NEET

Physics Class 11

Top Courses for NEET

Top Courses for NEET

Suggested Free Tests

Related Content

About NEET

NEET Preparation Material

How to Prepare for NEET Exam?

NCERT Based Study Material

NEET Mock Tests

Other Popular Exams

Company