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A ball is thrown vertically downward with a velocity of 20 metre per second from the top of a tower it hits the ground after sometime with a velocity of 80 metre per second the height of tower is?
Most Upvoted Answer
A ball is thrown vertically downward with a velocity of 20 metre per s...



Given data:
- Initial velocity (u) = 20 m/s
- Final velocity (v) = 80 m/s
- Acceleration due to gravity (g) = 9.8 m/s^2

Finding the time taken for the ball to hit the ground:
- Using the equation v = u + gt, where t is the time taken
- 80 = 20 + 9.8t
- t = 6.12 seconds

Calculating the height of the tower:
- Using the equation s = ut + (1/2)gt^2, where s is the height of the tower
- s = 20(6.12) + (1/2)(9.8)(6.12)^2
- s = 122.4 + 226.15
- s = 348.55 meters

Conclusion:
- The height of the tower is 348.55 meters.

Community Answer
A ball is thrown vertically downward with a velocity of 20 metre per s...
Solve it using : V² = U² + 2gh.
given V = 20m/s.
—> U = 80m/s.
—> g = 10m/s².
put the values in you'll get height of tower as 300m.
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