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A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second?
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A body covers 10 m in the seconds second and 25 m in fifth second of i...
Uniformly Accelerated Motion:
Uniformly accelerated motion is a type of motion in which the velocity of the body changes at a uniform rate. This means that the acceleration of the body remains constant throughout the motion.
Given Data:
Initial velocity (u) = 0 m/s
Distance covered in second second (s2) = 10 m
Distance covered in fifth second (s5) = 25 m
Time taken to cover the distance between s2 and s5 (t) = 5 - 2 = 3 seconds
Calculation:
Using the formula of uniformly accelerated motion:
s = ut + 1/2at^2
Where, s = distance, u = initial velocity, t = time taken, and a = acceleration
Distance covered in the second second:
s2 = ut + 1/2at^2
10 = 0 + 1/2a(2)^2
10 = 2a
a = 5 m/s^2
Distance covered in the fifth second:
s5 = ut + 1/2at^2
25 = 0 + 1/2a(5)^2
25 = 12.5a
a = 2 m/s^2
Distance covered in the seventh second:
Using the same formula, we can find the distance covered in the seventh second:
s7 = ut + 1/2at^2
s7 = 0 + 1/2(2)(7)^2
s7 = 49 m
Answer:
The body will cover a distance of 49 m in the seventh second of its motion.
Uniformly accelerated motion is a type of motion in which the velocity of the body changes at a uniform rate. This means that the acceleration of the body remains constant throughout the motion.
Given Data:
Initial velocity (u) = 0 m/s
Distance covered in second second (s2) = 10 m
Distance covered in fifth second (s5) = 25 m
Time taken to cover the distance between s2 and s5 (t) = 5 - 2 = 3 seconds
Calculation:
Using the formula of uniformly accelerated motion:
s = ut + 1/2at^2
Where, s = distance, u = initial velocity, t = time taken, and a = acceleration
Distance covered in the second second:
s2 = ut + 1/2at^2
10 = 0 + 1/2a(2)^2
10 = 2a
a = 5 m/s^2
Distance covered in the fifth second:
s5 = ut + 1/2at^2
25 = 0 + 1/2a(5)^2
25 = 12.5a
a = 2 m/s^2
Distance covered in the seventh second:
Using the same formula, we can find the distance covered in the seventh second:
s7 = ut + 1/2at^2
s7 = 0 + 1/2(2)(7)^2
s7 = 49 m
Answer:
The body will cover a distance of 49 m in the seventh second of its motion.
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A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second?
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A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second?.
A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body covers 10 m in the seconds second and 25 m in fifth second of its motion. If the motion is uniformly accelerated, how far will it go in the seventh second?.
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