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For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.
Correct answer is between '0.22,0.24'. Can you explain this answer?
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For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1),...
To complete the question, we need to know the value of molar conductivity at infinite dilution and 0.01 mol dm^-3. Without this information, we cannot calculate the dissociation constant of the weak acid.
However, we can use the given information to calculate the degree of dissociation of the weak acid at 0.04 mol dm^-3. The degree of dissociation, α, is given by:
α = (λ - λ0) / (λ∞ - λ0)
where λ is the molar conductivity at a given concentration, λ0 is the molar conductivity of the undissociated acid, and λ∞ is the molar conductivity at infinite dilution.
Using the given values, we have:
α = (4.3 - λ0) / (λ∞ - λ0)
We do not know the value of λ0 or λ∞, but we can still make some observations about the degree of dissociation. Since the molar conductivity at infinite dilution is always greater than the molar conductivity at any finite concentration, we know that λ∞ > 4.3. This means that the denominator in our equation is positive, so α must also be positive. In other words, the weak acid is dissociating to some extent at 0.04 mol dm^-3.
Without more information, we cannot say exactly how much the weak acid is dissociating. However, we can make some qualitative observations. If the weak acid were a strong acid, it would be almost completely dissociated at 0.04 mol dm^-3. Since the molar conductivity at infinite dilution is much larger than the value we have, we can infer that the weak acid is not very strong. Therefore, we would expect the degree of dissociation to be relatively small.
However, we can use the given information to calculate the degree of dissociation of the weak acid at 0.04 mol dm^-3. The degree of dissociation, α, is given by:
α = (λ - λ0) / (λ∞ - λ0)
where λ is the molar conductivity at a given concentration, λ0 is the molar conductivity of the undissociated acid, and λ∞ is the molar conductivity at infinite dilution.
Using the given values, we have:
α = (4.3 - λ0) / (λ∞ - λ0)
We do not know the value of λ0 or λ∞, but we can still make some observations about the degree of dissociation. Since the molar conductivity at infinite dilution is always greater than the molar conductivity at any finite concentration, we know that λ∞ > 4.3. This means that the denominator in our equation is positive, so α must also be positive. In other words, the weak acid is dissociating to some extent at 0.04 mol dm^-3.
Without more information, we cannot say exactly how much the weak acid is dissociating. However, we can make some qualitative observations. If the weak acid were a strong acid, it would be almost completely dissociated at 0.04 mol dm^-3. Since the molar conductivity at infinite dilution is much larger than the value we have, we can infer that the weak acid is not very strong. Therefore, we would expect the degree of dissociation to be relatively small.
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For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer?
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For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer?.
For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a weak acid at 298 K the molar conductivities (in ohm?1 m2 mol?1), at infinite dilution and 0.04 mol dm?3 are 4.3 × 10?3 and 1.0 × 10?3, respectively. The degree of dissociation of the acid (0.04 mol dm?3) at 298 K is ________.Correct answer is between '0.22,0.24'. Can you explain this answer?.
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