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Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L?
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Ground water contaminated with TCE is treated with powdered activated ...
Solution:

Given data:
Isotherm equation: Qeq = 129(Ce)0.73
Concentration of TCE in water (Co) = 1 mg/L
Target concentration of TCE in water (Ct) = 0.005 mg/L

To calculate:
Mass concentration of PAC required to reduce TCE concentration to 0.005 mg/L (mg PAC/L water)

Calculation:
1. Calculate the mass of TCE adsorbed on PAC at equilibrium (Qeq) using the isotherm equation:
Qeq = 129(Ce)0.73
Qeq = 129(1)0.73
Qeq = 129 mg TCE adsorbed per mg of PAC

2. Calculate the mass of TCE that needs to be adsorbed on PAC to reduce the concentration to 0.005 mg/L:
Ct = Qeq x Mpac/Vwater
Mpac/Vwater = Ct/Qeq
Mpac/Vwater = 0.005/129
Mpac/Vwater = 0.0000388 mg PAC/mg TCE

3. Convert the mass of PAC required to concentration:
Mass concentration of PAC = 0.0000388 x 1000
Mass concentration of PAC = 0.0388 mg PAC/L water

Therefore, the mass concentration of PAC required to reduce TCE concentration to 0.005 mg/L is 0.0388 mg/L. The correct option is (a) 0.3690 mg/L.

Explanation:
Groundwater contaminated with TCE can be treated with powdered activated carbon (PAC) by adsorption. The amount of TCE adsorbed on PAC at equilibrium depends on the concentration of TCE in water (Ce) and can be described by an isotherm equation. In this problem, the isotherm equation is given as Qeq = 129(Ce)0.73, where Qeq is the mass of TCE adsorbed per mass of PAC (mg/mg) and Ce is the concentration of TCE in water (mg/L).

To calculate the mass concentration of PAC required to reduce TCE concentration in water from 1 mg/L to 0.005 mg/L, we need to use the isotherm equation and mass balance equation. First, we calculate the amount of TCE adsorbed on PAC at equilibrium using the isotherm equation. Then we use the mass balance equation to calculate the mass of PAC required to adsorb the desired amount of TCE. Finally, we convert the mass of PAC to concentration by dividing by the volume of water treated.

The correct option for the mass concentration of PAC required to reduce TCE concentration to 0.005 mg/L is (a) 0.3690 mg/L.
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Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L?
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Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L?.
Solutions for Ground water contaminated with TCE is treated with powdered activated carbon by sorption (isotherm: Qeq = 129(Ce)0.73 where Qeg is mass eq eq of TCE adsorbed on PAC (mg/mg PAC); Co is eq concentration of dissolved TCE in water (mg/L)). If TCE concentration in water is 1 mg/L, what mass concentration of PAC must be used (mg PAC/L water) to reduce TCE concentration to 0.005 mg/L? (a) 0.3690 mg/L (c) 0.35 mg/L (d) 0.40 mg/L (b) 0.45 mg/L? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
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