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A synthetic sample of water is prepared by adding 100 mg kaolinite(a clay mineral), 200mg glucose,168 mg NaCl, 120mg MgSO4, and 111 mg CaCl2 to 1 liter of pure water. The concentration of fixed dissolved solids (FDS) in the mg/l is equal to?
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A synthetic sample of water is prepared by adding 100 mg kaolinite(a c...
Solution:
TS = 100 + 200 + 168 + 120 + 111 = 699 mg/ Lit
FDS = TS - Suspended solids
        = 699 - (100 + 200) = 399 mg /lit
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A synthetic sample of water is prepared by adding 100 mg kaolinite(a c...
Concentration of Fixed Dissolved Solids (FDS) in the Synthetic Water Sample

To determine the concentration of fixed dissolved solids (FDS) in the synthetic water sample, we need to calculate the total mass of the dissolved solids and then divide it by the volume of the water sample.

Given Information:
- Kaolinite (clay mineral): 100 mg
- Glucose: 200 mg
- NaCl: 168 mg
- MgSO4: 120 mg
- CaCl2: 111 mg
- Volume of water: 1 liter (1000 ml)

Calculations:

1. Calculate the total mass of dissolved solids:
Total mass of dissolved solids = mass of kaolinite + mass of glucose + mass of NaCl + mass of MgSO4 + mass of CaCl2
Total mass of dissolved solids = 100 mg + 200 mg + 168 mg + 120 mg + 111 mg
Total mass of dissolved solids = 699 mg

2. Convert the volume of water to liters:
Volume of water = 1 liter

3. Calculate the concentration of fixed dissolved solids (FDS):
Concentration of FDS = Total mass of dissolved solids / Volume of water
Concentration of FDS = 699 mg / 1 liter
Concentration of FDS = 699 mg/L

Explanation:

The concentration of fixed dissolved solids (FDS) in the synthetic water sample is 699 mg/L. This means that for every liter of water in the sample, there are 699 mg of dissolved solids.

The dissolved solids in the sample consist of various substances, including kaolinite (a clay mineral), glucose, NaCl, MgSO4, and CaCl2. These substances contribute to the overall concentration of fixed dissolved solids.

The calculation involves summing up the masses of all the dissolved solids and dividing it by the volume of water. This gives us the concentration of FDS in mg/L.

It is important to note that the concentration of FDS is a measure of the total amount of dissolved solids in the water sample. It does not provide information about the specific composition or individual concentrations of each dissolved solid.

In summary, the concentration of fixed dissolved solids (FDS) in the synthetic water sample is 699 mg/L, which is determined by calculating the total mass of dissolved solids and dividing it by the volume of water.
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A synthetic sample of water is prepared by adding 100 mg kaolinite(a clay mineral), 200mg glucose,168 mg NaCl, 120mg MgSO4, and 111 mg CaCl2 to 1 liter of pure water. The concentration of fixed dissolved solids (FDS) in the mg/l is equal to?
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