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A journal bearing has a shaft diameter of 40 mm and a length of 40 mm the shaft is rotating at 20 rad/sec and the viscosity of the lubricant is 20 MPa -sec the clearance is 0.020 mm the loss of torque to the viscosity of the lubrication is approximately?
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A journal bearing has a shaft diameter of 40 mm and a length of 40 mm ...
Calculation of Loss of Torque in a Journal Bearing


Given Parameters:


  • Diameter of Shaft (D) = 40 mm

  • Length of Shaft (L) = 40 mm

  • Rotational Speed (ω) = 20 rad/sec

  • Viscosity of Lubricant (μ) = 20 MPa-sec

  • Clearance (c) = 0.020 mm



Formula:

The loss of torque in a journal bearing is given by the formula:
T = μAωc

where T is the loss of torque, μ is the viscosity of the lubricant, A is the area of the bearing surface, ω is the rotational speed, and c is the clearance.

Calculation:


  • Area of Bearing Surface (A) = πDL

  • Substituting the given values in the formula:

  • T = 20 x 10^6 x π x 40 x 40 x 0.020 x 20

  • Simplifying the equation, we get:

  • T = 64 N-mm



Explanation:

The loss of torque in a journal bearing is due to the viscosity of the lubricant. When the shaft rotates, it creates a pressure difference that causes the lubricant to flow through the clearance between the shaft and the bearing surface. This flow of lubricant creates a shear stress that opposes the motion of the shaft, resulting in a loss of torque. The magnitude of the loss of torque depends on the viscosity of the lubricant, the area of the bearing surface, the clearance, and the rotational speed. In this case, the loss of torque is approximately 64 N-mm.
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A journal bearing has a shaft diameter of 40 mm and a length of 40 mm the shaft is rotating at 20 rad/sec and the viscosity of the lubricant is 20 MPa -sec the clearance is 0.020 mm the loss of torque to the viscosity of the lubrication is approximately?
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