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In the following question, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.
Quantity I: What is volume (cm3) of spherical ball having surface area equals to 1386 cm2?
Quantity II: What is compound interest(in Rs.) earned on ₹28500 at the rate of 8% for two years?
  • a)
    Quantity I > Quantity II
  • b)
    Quantity I < quantity="" />
  • c)
    Quantity I ≥ Quantity II
  • d)
    Quantity I ≤ Quantity II
  • e)
    Quantity I = Quantity II or the relation can't be determined
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In the following question, two statements numbered I and II are given...
Quantity I
Surface area of sphere = 4πR2 = 1386
R2 = (1386 × 7)/(4 × 22) = 110.25
Radius = 10.5 cm
Volume = 4/3πR3 = (4/3 × 22/7 × 10.5 × 10.5 × 10.5) = 4851 cm3.
Quantity II:
CI = P × ((1 + R/100)2 - 1)
CI = 28500 × (108/100)2 - 1)
CI = 28500 × 1664/10000 = ₹4742.4
Hence, Quantity I > Quantity II
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In the following question, two statements numbered I and II are given. On solving them, we get quantities I and II respectively. Solve for both the quantities and choose the correct option.Quantity I: What is volume (cm3) of spherical ball having surface area equals to 1386 cm2?Quantity II: What is compound interest(in Rs.) earned on ₹28500 at the rate of 8% for two years?a)Quantity I > Quantity IIb)Quantity I c)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or the relation can't be determinedCorrect answer is option 'A'. Can you explain this answer?
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