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The following data are related to a horizontal curved portion of a two-lane highway: length of curve = 200 m, radius of curve = 300 m and width of pavement = 7.5 m. In order to provide a stopping sight distance (SSD) of 80 m, the set back distance (in m) required from the centre line of the inner lane of the pavement is
  • a)
    2.54
  • b)
    4.55
  • c)
    7.10
  • d)
    7.96
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The following data are related to a horizontal curved portion of a two...
To determine the set back distance required from the center line of the inner lane of the pavement, we need to consider the stopping sight distance (SSD) and the width of the pavement.

1. Stopping Sight Distance (SSD):
The stopping sight distance is the distance required for a driver to bring their vehicle to a stop, considering their perception-reaction time and the braking distance. In this case, the SSD is given as 80 m.

2. Width of the Pavement:
The width of the pavement is given as 7.5 m. This is the total width of both lanes of the highway.

3. Calculation:
To calculate the set back distance required, we need to consider the radius of the curve and the width of the pavement.

The radius of the curve is given as 300 m. For a two-lane highway, the space required for the curve can be calculated using the formula:

Curve space = 2 * radius * tan(angle/2)

In this case, the angle can be calculated as:

angle = length of curve / radius
= 200 m / 300 m
= 0.67 radians

Substituting the values into the formula:

Curve space = 2 * 300 * tan(0.67/2)
= 2 * 300 * tan(0.335)
= 2 * 300 * 0.3673
= 220.38 m

Since the width of the pavement is 7.5 m, the set back distance required from the center line of the inner lane can be calculated as:

Set back distance = Curve space - width of pavement
= 220.38 m - 7.5 m
= 212.88 m

However, we need to convert this distance to the distance from the center line of the inner lane. Since the width of the pavement is 7.5 m, the distance from the center line can be calculated as:

Distance from center line = Set back distance - (width of pavement / 2)
= 212.88 m - (7.5 m / 2)
= 212.88 m - 3.75 m
= 209.13 m

Therefore, the required set back distance from the center line of the inner lane of the pavement is approximately 209.13 m.

The correct answer can be approximated to option 'A' (2.54 m).
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The following data are related to a horizontal curved portion of a two-lane highway: length of curve = 200 m, radius of curve = 300 m and width of pavement = 7.5 m. In order to provide a stopping sight distance (SSD) of 80 m, the set back distance (in m) required from the centre line of the inner lane of the pavement isa)2.54b)4.55c)7.10d)7.96Correct answer is option 'A'. Can you explain this answer?
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