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A uniform volume charge density ρv= 5 µC/m3 is present in the spherical shell of 0.9 < r="" />< 1="" m="" and="" />v = 0 elsewhere. The charge present in the shell approximately is
- a)5.675 µC
- b)11.35 µC
- c)5 µC
- d)0 µC
Correct answer is option 'A'. Can you explain this answer?
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A uniform volume charge density ρv= 5 µC/m3 is present in the spheric...
Q = 
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Q = 
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Q = 5.675µC
Most Upvoted Answer
A uniform volume charge density ρv= 5 µC/m3 is present in the spheric...
The volume charge density ρv is given as 5 µC/m^3. We need to find the charge present in the spherical shell.
To find the charge present in the shell, we need to first calculate the volume of the shell and then multiply it by the volume charge density.
Let's assume the radius of the spherical shell as R.
1. Calculating the volume of the shell:
The volume of a spherical shell can be calculated by subtracting the volume of the inner sphere from the volume of the outer sphere.
The volume of the inner sphere with radius R = 0.9R is given by:
V_inner = (4/3)π(0.9R)^3
The volume of the outer sphere with radius R is given by:
V_outer = (4/3)πR^3
The volume of the shell is the difference between the volumes of the outer and inner spheres:
V_shell = V_outer - V_inner
= (4/3)πR^3 - (4/3)π(0.9R)^3
= (4/3)πR^3 - (4/3)π(0.729R^3)
= (4/3)πR^3 - (4/3)π(0.729R^3)
= (4/3)πR^3 - (2.916/3)πR^3
= (1.084/3)πR^3
2. Calculating the charge present in the shell:
The charge present in the shell can be calculated by multiplying the volume of the shell by the volume charge density:
Q_shell = V_shell * ρv
= (1.084/3)πR^3 * 5 µC/m^3
= (5.42/3)πR^3 µC
Therefore, the charge present in the shell is approximately 5.42/3 times πR^3 µC.
Since the options provided do not match the calculated value, it seems like there may be an error in the given question or options. However, if we round the calculated value to two decimal places, the closest option is 5.68 µC, which corresponds to option A.
To find the charge present in the shell, we need to first calculate the volume of the shell and then multiply it by the volume charge density.
Let's assume the radius of the spherical shell as R.
1. Calculating the volume of the shell:
The volume of a spherical shell can be calculated by subtracting the volume of the inner sphere from the volume of the outer sphere.
The volume of the inner sphere with radius R = 0.9R is given by:
V_inner = (4/3)π(0.9R)^3
The volume of the outer sphere with radius R is given by:
V_outer = (4/3)πR^3
The volume of the shell is the difference between the volumes of the outer and inner spheres:
V_shell = V_outer - V_inner
= (4/3)πR^3 - (4/3)π(0.9R)^3
= (4/3)πR^3 - (4/3)π(0.729R^3)
= (4/3)πR^3 - (4/3)π(0.729R^3)
= (4/3)πR^3 - (2.916/3)πR^3
= (1.084/3)πR^3
2. Calculating the charge present in the shell:
The charge present in the shell can be calculated by multiplying the volume of the shell by the volume charge density:
Q_shell = V_shell * ρv
= (1.084/3)πR^3 * 5 µC/m^3
= (5.42/3)πR^3 µC
Therefore, the charge present in the shell is approximately 5.42/3 times πR^3 µC.
Since the options provided do not match the calculated value, it seems like there may be an error in the given question or options. However, if we round the calculated value to two decimal places, the closest option is 5.68 µC, which corresponds to option A.
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