The no load voltage of a transformer is 440 V and its load current is 10 A. If the equivalent resistance & reactance are 0.12 Ω and 2.42 Ω and is operating at a power factor of 0.8 lagging, then find the % voltage regulation of the transformer.a)3.545%b)3.546%c)3.547%d)3.548%Correct answer is option 'B'. Can you explain this answer?

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Answer

Of the transformer is 4 Ω, the load power factor is 0.8 lagging, and the primary voltage is 220 V, we can calculate the primary current using the formula:

Primary current = Load current / (Power factor x Efficiency)

Since the load power factor is 0.8 lagging, the efficiency is 1 (since no efficiency is given), the primary current is:

Primary current = 10 A / (0.8 x 1) = 12.5 A

Using Ohm's law, we can calculate the equivalent impedance of the transformer:

Equivalent impedance = No load voltage / Primary current
= 440 V / 12.5 A
= 35.2 Ω

Since the equivalent resistance is given as 4 Ω, we can subtract it from the equivalent impedance to find the equivalent reactance:

Equivalent reactance = Equivalent impedance - Equivalent resistance
= 35.2 Ω - 4 Ω
= 31.2 Ω

Therefore, the equivalent reactance of the transformer is 31.2 Ω.

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