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A photo-detector circuit shown in figure. The photo-diode has an active area of 10+2 cm2 and sensitivity of 0.55 A/W. When light of intensity 10mW/cm2 falls on the photo-diode, the output voltage VO is ___ volt.
  • a)
    -14
  • b)
    -13
Correct answer is between '-14,-13'. Can you explain this answer?
Verified Answer
A photo-detector circuit shown in figure. The photo-diode has an acti...
The photo diode current is
I = light intensity x sensitivity x Area
= 10 x 10-3 x 0.55 x 102 x 10-4
= 0.55 x 10-4 A
Hence Vo1 = (-100k) x I = -5.5 volt
Now for 2nd op-amp,
Current through 20 kΩ resistor is
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A photo-detector circuit shown in figure. The photo-diode has an active area of 10+2 cm2 and sensitivity of 0.55 A/W. When light of intensity 10mW/cm2 falls on the photo-diode, the output voltage VO is ___ volt.a)-14b)-13Correct answer is between '-14,-13'. Can you explain this answer?
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A photo-detector circuit shown in figure. The photo-diode has an active area of 10+2 cm2 and sensitivity of 0.55 A/W. When light of intensity 10mW/cm2 falls on the photo-diode, the output voltage VO is ___ volt.a)-14b)-13Correct answer is between '-14,-13'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A photo-detector circuit shown in figure. The photo-diode has an active area of 10+2 cm2 and sensitivity of 0.55 A/W. When light of intensity 10mW/cm2 falls on the photo-diode, the output voltage VO is ___ volt.a)-14b)-13Correct answer is between '-14,-13'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A photo-detector circuit shown in figure. The photo-diode has an active area of 10+2 cm2 and sensitivity of 0.55 A/W. When light of intensity 10mW/cm2 falls on the photo-diode, the output voltage VO is ___ volt.a)-14b)-13Correct answer is between '-14,-13'. Can you explain this answer?.
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