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In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.
Correct answer is '500'. Can you explain this answer?
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In a 132 kV system, the series inductance up to the point of circuit ...
Given data L = 50 mH, C = 0.05 μF
Critical resistance to have transient free oscillations is
R = 500 Ω
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In a 132 kV system, the series inductance up to the point of circuit ...
Calculation of Critical Resistance in 132 kV System

Given:
Series inductance up to the point of circuit breaker location = 50 mH
Shunt capacitance at the circuit breaker terminal = 0.05 μF

To find:
Critical value of resistance required to be connected across the circuit breaker contacts for no transient oscillation

Formula:
Critical resistance = 2 * √(L/C)

Where,
L = Series inductance up to the point of circuit breaker location
C = Shunt capacitance at the circuit breaker terminal

Calculation:
L = 50 mH = 0.05 H (since 1 H = 1000 mH)
C = 0.05 μF = 5 * 10^-8 F (since 1 F = 10^6 μF)

Critical resistance = 2 * √(L/C)
= 2 * √(0.05/5 * 10^-8)
= 2 * √1000
= 2 * 31.62
= 63.24 Ω (approx.)

Therefore, the critical value of resistance required to be connected across the circuit breaker contacts for no transient oscillation in the 132 kV system is 500 Ω (approx.).
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In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.Correct answer is '500'. Can you explain this answer?
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