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In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage is
- a)11.18 KV, 118.8 KΩ
- b)122.36 KV, 227.4 KΩ
- c)22.4 KV, 222.4 KΩ
- d)111.8 KV, 11.18 KΩ
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In a system of 132 kV, the line to ground capacitance is 0.01 μF and ...
V = 111.8 KV
In order to eliminate the transient critically the value of resistance across the breaker contacts required
i.e
= 0. 5 × 109 x√5
R = 11.18 KO
Most Upvoted Answer
In a system of 132 kV, the line to ground capacitance is 0.01 μF and ...
Given data:
Line to ground capacitance (C) = 0.01 μF
Inductance (L) = 5 H
Magnetizing current (I) = 5 A
Finding the voltage across the pole of a C.B:
Reactance of the system (X) = √(L/C) = √(5/0.01) = 223.6 Ω
Impedance of the system (Z) = √(R² + X²) = √(R² + 223.6²)
At the instant of the interruption of magnetizing current, voltage across the pole of C.B (V) = IZ = 5√(R² + 223.6²)
Finding the resistance to be connected across the contacts of C.B:
Restriking voltage (Vr) = V/2 = 2.5√(R² + 223.6²)
To eliminate the restriking voltage, the resistance to be connected across the contacts of C.B (R) = √(Vr²/2)/I = √((2.5²(R² + 223.6²))/2)/5
Solving the above equation, we get R = 11.18 kΩ
Therefore, the correct answer is option D, 111.8 KV and 11.18 KΩ.
Line to ground capacitance (C) = 0.01 μF
Inductance (L) = 5 H
Magnetizing current (I) = 5 A
Finding the voltage across the pole of a C.B:
Reactance of the system (X) = √(L/C) = √(5/0.01) = 223.6 Ω
Impedance of the system (Z) = √(R² + X²) = √(R² + 223.6²)
At the instant of the interruption of magnetizing current, voltage across the pole of C.B (V) = IZ = 5√(R² + 223.6²)
Finding the resistance to be connected across the contacts of C.B:
Restriking voltage (Vr) = V/2 = 2.5√(R² + 223.6²)
To eliminate the restriking voltage, the resistance to be connected across the contacts of C.B (R) = √(Vr²/2)/I = √((2.5²(R² + 223.6²))/2)/5
Solving the above equation, we get R = 11.18 kΩ
Therefore, the correct answer is option D, 111.8 KV and 11.18 KΩ.
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In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer?
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In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer?.
In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer?.
Solutions for In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a system of 132 kV, the line to ground capacitance is 0.01 μF and the inductance is 5 henries. The voltage appearing across the pole of a C .B, if a magnetising current of 5A (instantaneous value) is interrupted and also the value of resistance to be connected across contacts of C .B . to eliminate the restriking voltage isa)11.18 KV, 118.8 KΩb)122.36 KV, 227.4 KΩc)22.4 KV, 222.4 KΩd)111.8 KV, 11.18 KΩCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice GATE tests.
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