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An epicyclic gear train is shown in the figure below. The number of teeths on A and B are 80 and 200. The speed of arm a if A rotates at 100 rpm clockwise and B is stationary, will be?
  • a)
    28.6 rpm clockwise
  • b)
    57.2 rpm, any direction
  • c)
    14.3 rpm counter-clockwise
  • d)
    28.6 rpm counter-clockwise
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An epicyclic gear train is shown in the figure below. The number of te...
TA = 80, Ta = 200
TC = 60
Given, y+x = 1
∴ Om solving, x = 71.4 and y = 28.6
Speed of arm a = 28.6 rpm clockwise
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Most Upvoted Answer
An epicyclic gear train is shown in the figure below. The number of te...
TA = 80, Ta = 200
TC = 60
Given, y+x = 1
∴ Om solving, x = 71.4 and y = 28.6
Speed of arm a = 28.6 rpm clockwise
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An epicyclic gear train is shown in the figure below. The number of teeths on A and B are 80 and 200. The speed of arm a if A rotates at 100 rpm clockwise and B is stationary, will be?a)28.6 rpm clockwiseb)57.2 rpm, any directionc)14.3 rpm counter-clockwised)28.6 rpm counter-clockwiseCorrect answer is option 'A'. Can you explain this answer?
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