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10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is made of steel of thermal conductivity 100 kJ/m-hr-deg. The temperature at the root is 500o C and it is expose to a temperature of 850o C. The shaft may be treated as a fin losing heat at the tip having film coefficient of 1100 kJ/m2-hr-deg. The temperature at the middle of the shaft will be
  • a)
    820o C
  • b)
    723o C
  • c)
    880o C
  • d)
    778o C
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is m...
For a fin losing heat at the tip,
Then, ml = 49.44 x 0.10 = 4.944
And
sinh ml = 70.1617, cosh ml = 70.1688, tanh ml = 0.9999
sinh ml = 70.1617, cosh ml = 70.1688, tanh mi = 0.9999
Then, for a fin losing heat at the tip, the temperature distribution is prescribed by the relation:
From this expression, temperature at any distance x from the root can be worked out. At the mid
of the shaft, x = .05m
Cosh m(f — x) = cosh 49.44(0.10 — 0.05) = 5.965
sinh m ( l — x ) = sinh 49 .44 (0 .10 — 0.05 ) = 5.881
So
⇒ tx = 820.322°C
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Most Upvoted Answer
10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is m...
For a fin losing heat at the tip,
Then, ml = 49.44 x 0.10 = 4.944
And
sinh ml = 70.1617, cosh ml = 70.1688, tanh ml = 0.9999
sinh ml = 70.1617, cosh ml = 70.1688, tanh mi = 0.9999
Then, for a fin losing heat at the tip, the temperature distribution is prescribed by the relation:
From this expression, temperature at any distance x from the root can be worked out. At the mid
of the shaft, x = .05m
Cosh m(f — x) = cosh 49.44(0.10 — 0.05) = 5.965
sinh m ( l — x ) = sinh 49 .44 (0 .10 — 0.05 ) = 5.881
So
⇒ tx = 820.322°C
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10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is made of steel of thermal conductivity 100 kJ/m-hr-deg. The temperature at the root is 500o C and it is expose to a temperature of 850o C. The shaft may be treated as a fin losing heat at the tip having film coefficient of 1100 kJ/m2-hr-deg. The temperature at the middle of the shaft will bea)820o Cb)723o Cc)880o Cd)778o CCorrect answer is option 'A'. Can you explain this answer?
Question Description
10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is made of steel of thermal conductivity 100 kJ/m-hr-deg. The temperature at the root is 500o C and it is expose to a temperature of 850o C. The shaft may be treated as a fin losing heat at the tip having film coefficient of 1100 kJ/m2-hr-deg. The temperature at the middle of the shaft will bea)820o Cb)723o Cc)880o Cd)778o CCorrect answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about 10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is made of steel of thermal conductivity 100 kJ/m-hr-deg. The temperature at the root is 500o C and it is expose to a temperature of 850o C. The shaft may be treated as a fin losing heat at the tip having film coefficient of 1100 kJ/m2-hr-deg. The temperature at the middle of the shaft will bea)820o Cb)723o Cc)880o Cd)778o CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10 cm long, 9 cm2 cross-sectional area and 20 cm perimeter shaft is made of steel of thermal conductivity 100 kJ/m-hr-deg. The temperature at the root is 500o C and it is expose to a temperature of 850o C. The shaft may be treated as a fin losing heat at the tip having film coefficient of 1100 kJ/m2-hr-deg. The temperature at the middle of the shaft will bea)820o Cb)723o Cc)880o Cd)778o CCorrect answer is option 'A'. Can you explain this answer?.
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