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It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.
- a)133
- b)93
- c)2.33
- d)45
Correct answer is option 'A'. Can you explain this answer?
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It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-th...
12000 × 16 = tfield
⟹ 192000 sec = 133 days
Most Upvoted Answer
It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-th...
Given information:
- Consolidation time in the laboratory: 3 minutes 30 seconds
- Consolidation percentage: 40%
- Thickness of clay layer in the laboratory: 35 mm
- Thickness of clay layer in the field: 4 m
- Drainage condition: 2-way
- There is a rock layer at the bottom of the clay layer in the field.
Approach:
To find the time required for consolidation in the field, we can use the concept of time factor (T) and the thickness ratio (H/L) for consolidation.
Step 1: Calculation of laboratory time factor (Tl):
Given: Consolidation time in the laboratory = 3 minutes 30 seconds = 3.5 minutes
The laboratory time factor (Tl) can be calculated using the following formula:
Tl = T × (Hl2/Hl1) × log(L2/L1)
Where,
Tl = Laboratory time factor
T = Consolidation time in minutes
Hl1 = Initial thickness of clay in the laboratory (35 mm)
Hl2 = Final thickness of clay in the laboratory (35 mm + 40% of 35 mm = 49 mm)
L1 = Initial length of clay layer in the laboratory (considered as 1 unit)
L2 = Final length of clay layer in the laboratory (considered as 1 unit)
Step 2: Calculation of field time factor (Tf):
Given: Thickness of clay layer in the field = 4 m
The field time factor (Tf) can be calculated using the following formula:
Tf = Tl × (Hf2/Hf1) × log(Lf2/Lf1)
Where,
Tf = Field time factor
Hf1 = Initial thickness of clay in the field (4 m)
Hf2 = Final thickness of clay in the field (4 m + 40% of 4 m)
Lf1 = Initial length of clay layer in the field (considered as 1 unit)
Lf2 = Final length of clay layer in the field (considered as 1 unit)
Step 3: Calculation of time required for consolidation in the field:
The time required for consolidation in the field can be calculated using the following formula:
Tf = T × (Hf2/Hf1) × log(Lf2/Lf1)
Solving this equation for T, we can find the time required for consolidation in the field.
Calculation:
Given data:
Consolidation time in the laboratory (T) = 3.5 minutes
Initial thickness of clay in the laboratory (Hl1) = 35 mm
Final thickness of clay in the laboratory (Hl2) = 49 mm
Initial length of clay layer in the laboratory (L1) = 1 unit
Final length of clay layer in the laboratory (L2) = 1 unit
Initial thickness of clay in the field (Hf1) = 4 m
Final thickness of clay in the field (Hf2) = 4 m + 40% of 4 m = 4 m + 1.6 m = 5.6 m
Initial length of clay layer in the field (Lf1) = 1 unit
Final length of clay
- Consolidation time in the laboratory: 3 minutes 30 seconds
- Consolidation percentage: 40%
- Thickness of clay layer in the laboratory: 35 mm
- Thickness of clay layer in the field: 4 m
- Drainage condition: 2-way
- There is a rock layer at the bottom of the clay layer in the field.
Approach:
To find the time required for consolidation in the field, we can use the concept of time factor (T) and the thickness ratio (H/L) for consolidation.
Step 1: Calculation of laboratory time factor (Tl):
Given: Consolidation time in the laboratory = 3 minutes 30 seconds = 3.5 minutes
The laboratory time factor (Tl) can be calculated using the following formula:
Tl = T × (Hl2/Hl1) × log(L2/L1)
Where,
Tl = Laboratory time factor
T = Consolidation time in minutes
Hl1 = Initial thickness of clay in the laboratory (35 mm)
Hl2 = Final thickness of clay in the laboratory (35 mm + 40% of 35 mm = 49 mm)
L1 = Initial length of clay layer in the laboratory (considered as 1 unit)
L2 = Final length of clay layer in the laboratory (considered as 1 unit)
Step 2: Calculation of field time factor (Tf):
Given: Thickness of clay layer in the field = 4 m
The field time factor (Tf) can be calculated using the following formula:
Tf = Tl × (Hf2/Hf1) × log(Lf2/Lf1)
Where,
Tf = Field time factor
Hf1 = Initial thickness of clay in the field (4 m)
Hf2 = Final thickness of clay in the field (4 m + 40% of 4 m)
Lf1 = Initial length of clay layer in the field (considered as 1 unit)
Lf2 = Final length of clay layer in the field (considered as 1 unit)
Step 3: Calculation of time required for consolidation in the field:
The time required for consolidation in the field can be calculated using the following formula:
Tf = T × (Hf2/Hf1) × log(Lf2/Lf1)
Solving this equation for T, we can find the time required for consolidation in the field.
Calculation:
Given data:
Consolidation time in the laboratory (T) = 3.5 minutes
Initial thickness of clay in the laboratory (Hl1) = 35 mm
Final thickness of clay in the laboratory (Hl2) = 49 mm
Initial length of clay layer in the laboratory (L1) = 1 unit
Final length of clay layer in the laboratory (L2) = 1 unit
Initial thickness of clay in the field (Hf1) = 4 m
Final thickness of clay in the field (Hf2) = 4 m + 40% of 4 m = 4 m + 1.6 m = 5.6 m
Initial length of clay layer in the field (Lf1) = 1 unit
Final length of clay
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It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer?
Question Description
It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer?.
It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It required a time of 3 min 30 sec for 40% consolidation of a 35-mm-thick clay layer (2- way drainage condition) in the laboratory. How long (in days) will it take for a 4-m-thick clay layer of the same clay in the field under the same pressure increment to reach 40% consolidation? In the site, there is a rock layer at the bottom of the clay.a)133b)93c)2.33d)45Correct answer is option 'A'. Can you explain this answer?.
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