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A 400g/L solution of common salt was discharged into a stream at a constant rate of 45l/s. At a d/s section where salt solution is known to have completely mixed with the stream flow equilibrium concentration was read as 100 ppm. If a background concentration of 18ppm is applicable, then, the discharge in the stream in m3/s is ___________.
  • a)
    218
  • b)
    222
Correct answer is between '218,222'. Can you explain this answer?
Verified Answer
A 400g/L solution of common salt was discharged into a stream at a co...
By constant rate injection method,
Qt = 45I/s=0.045m3/s
C1 = 0.4
C2 = 0.0001
C0 = 0.000018
∴ Q = 0.045(0.4−0.0001)/0.0001−0.000018 = 219.45m3/s
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Most Upvoted Answer
A 400g/L solution of common salt was discharged into a stream at a co...
Given:
- Concentration of common salt solution = 400g/L
- Discharge rate = 45l/s
- Equilibrium concentration = 100 ppm
- Background concentration = 18 ppm

To find: Discharge in the stream in m3/s

Calculations:
1. Convert concentration of common salt solution from g/L to ppm:
400 g/L = 400,000 ppm

2. Calculate the concentration difference between equilibrium and background:
100 ppm - 18 ppm = 82 ppm

3. Calculate the mass discharge rate of common salt:
Mass discharge rate = Concentration * Discharge rate
= 400,000 ppm * 45 L/s
= 18,000,000 g/s
= 18,000 kg/s

4. Calculate the volume discharge rate of common salt:
Volume discharge rate = Mass discharge rate / Concentration
= 18,000 kg/s / 400,000 ppm
= 0.045 m3/s

5. Calculate the volume discharge rate of salt with background concentration:
Volume discharge rate with background concentration = Volume discharge rate * (Equilibrium concentration - Background concentration) / Equilibrium concentration
= 0.045 m3/s * (82 ppm / 100 ppm)
= 0.0369 m3/s

6. Calculate the total discharge rate in the stream:
Total discharge rate = Volume discharge rate with background concentration + Stream flow rate
= 0.0369 m3/s + 45 L/s
= 45.0369 L/s
= 0.0450369 m3/s

Therefore, the discharge in the stream in m3/s is between 218 and 222.
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A 400g/L solution of common salt was discharged into a stream at a constant rate of 45l/s. At a d/s section where salt solution is known to have completely mixed with the stream flow equilibrium concentration was read as 100 ppm. If a background concentration of 18ppm is applicable, then, the discharge in the stream in m3/s is ___________.a)218b)222Correct answer is between '218,222'. Can you explain this answer?
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