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A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate is
- a)90
- b)80
- c)70
- d)60
Correct answer is option 'C'. Can you explain this answer?
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A horizontal jet of water with its cross–sectional area of 0.0028 m2 ...
The Jet impacts plate as shown
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the velocity in x direction becomes zero after impact so using impulse momentum theorem
F = ρ0Q1V1 − ρωQ2V2 = ρωQ(V1−0)
Q = AV = 0.0028 × 5 = 0.014 ρω = 1000kg/m3
So ForceF = 1000 × 0.014 × (5−0)
= 70N
Most Upvoted Answer
A horizontal jet of water with its cross–sectional area of 0.0028 m2 ...
Given data:
- Cross-sectional area of the jet (A) = 0.0028 m^2
- Velocity of the jet (v) = 5 m/s
Formula:
The force exerted by a fluid on a surface is given by the formula:
F = ρ * A * v^2,
where ρ is the density of the fluid, A is the cross-sectional area of the jet, and v is the velocity of the jet.
Calculations:
1. Density of water:
The density of water is approximately 1000 kg/m^3.
2. Substituting the given values into the formula:
F = 1000 * 0.0028 * (5)^2
= 1000 * 0.0028 * 25
= 70 N
Therefore, the force of impact of the jet on the plate is 70 N.
Conclusion:
The correct answer is option C) 70.
- Cross-sectional area of the jet (A) = 0.0028 m^2
- Velocity of the jet (v) = 5 m/s
Formula:
The force exerted by a fluid on a surface is given by the formula:
F = ρ * A * v^2,
where ρ is the density of the fluid, A is the cross-sectional area of the jet, and v is the velocity of the jet.
Calculations:
1. Density of water:
The density of water is approximately 1000 kg/m^3.
2. Substituting the given values into the formula:
F = 1000 * 0.0028 * (5)^2
= 1000 * 0.0028 * 25
= 70 N
Therefore, the force of impact of the jet on the plate is 70 N.
Conclusion:
The correct answer is option C) 70.
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A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer?
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A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer?.
A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal jet of water with its cross–sectional area of 0.0028 m2 hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate isa)90b)80c)70d)60Correct answer is option 'C'. Can you explain this answer?.
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