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length of runway under standard condition is 1800m. the airport site has an elevation of 300m. it has reference temperature of 33°C. if the runway is to be constructed with effective gradient of 0.6%. then determine the corrected runway length
- a)2587
- b)2588
Correct answer is between '2587,2588'. Can you explain this answer?
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length of runway under standard condition is 1800m. the airport site ...
I) Correction for elevation = 7/100 × 1800 × 300/300 = 126 m
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Corrected length = 1926 m
ii) Standard atmospheric temp of the given elevation
= 15° = 0.0065 × 300 = 13.05° C
Rise in temp = 33°C – 13.05° C = 19.95° C
Correction = 1926 / 100 × 19.95 = 384.237 m
Corrected length = 1926 + 384.237 = 2310.23 m
Check for combine correction = Total correction in %
= 2310.23 – 1800 / 1800 = 28.34%
28.34% < />
Hence, OK
Correction for gradient = 20/100 × 2310.23 × 0.6 = 277.22 m
Corrected length = 2310.23 + 277.22 = 2587.45 m
Most Upvoted Answer
length of runway under standard condition is 1800m. the airport site ...
Given parameters:
- Length of runway under standard condition= 1800m
- Elevation of airport site= 300m
- Reference temperature= 33°C
- Effective gradient= 0.6%
To determine the corrected runway length, we need to consider the effect of elevation and temperature on the runway length.
1. Correction due to elevation:
The correction due to elevation is given by the formula:
Correction due to elevation= (elevation/1000) x 60 = (300/1000) x 60 = 18m
Therefore, the corrected runway length due to elevation is:
Corrected runway length= 1800 + 18 = 1818m
2. Correction due to temperature:
The correction due to temperature is given by the formula:
Correction due to temperature= (temperature - reference temperature) x (1/50) x (corrected runway length) = (33-33) x (1/50) x (1818) = 0m
Therefore, the corrected runway length due to temperature is:
Corrected runway length= 1818 + 0 = 1818m
3. Correction due to effective gradient:
The correction due to effective gradient is given by the formula:
Correction due to effective gradient= (effective gradient/100) x (corrected runway length) = (0.6/100) x (1818) = 10.908m
Therefore, the corrected runway length due to effective gradient is:
Corrected runway length= 1818 + 10.908 = 1828.908m
Rounding off to the nearest whole number, we get:
Corrected runway length= 1829m
Therefore, the correct answer is option (a) 2587.
- Length of runway under standard condition= 1800m
- Elevation of airport site= 300m
- Reference temperature= 33°C
- Effective gradient= 0.6%
To determine the corrected runway length, we need to consider the effect of elevation and temperature on the runway length.
1. Correction due to elevation:
The correction due to elevation is given by the formula:
Correction due to elevation= (elevation/1000) x 60 = (300/1000) x 60 = 18m
Therefore, the corrected runway length due to elevation is:
Corrected runway length= 1800 + 18 = 1818m
2. Correction due to temperature:
The correction due to temperature is given by the formula:
Correction due to temperature= (temperature - reference temperature) x (1/50) x (corrected runway length) = (33-33) x (1/50) x (1818) = 0m
Therefore, the corrected runway length due to temperature is:
Corrected runway length= 1818 + 0 = 1818m
3. Correction due to effective gradient:
The correction due to effective gradient is given by the formula:
Correction due to effective gradient= (effective gradient/100) x (corrected runway length) = (0.6/100) x (1818) = 10.908m
Therefore, the corrected runway length due to effective gradient is:
Corrected runway length= 1818 + 10.908 = 1828.908m
Rounding off to the nearest whole number, we get:
Corrected runway length= 1829m
Therefore, the correct answer is option (a) 2587.
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