All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
GATE Exam  >  GATE Questions  >   Eight voice signals, each limited to 4 kHz a... Start Learning for Free
SaveJoin the Discussion on the App
Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____
Correct answer is '512'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Verified Answer
Eight voice signals, each limited to 4 kHz and sampled at Nyquist rat...
Nyquist rate = 4×103×2 = 8×103 samples/sec
256 levels = 8 bits.
So one sample is represented by 8 -bit. So total = 8×8×103 bits/sec
For 8 voice signal = 8×8×8×103 bits/sec
= 512 kbps
View all questions of this test
Most Upvoted Answer
Eight voice signals, each limited to 4 kHz and sampled at Nyquist rat...

Calculation of Bit Transmission Rate for Time-Division Multiplexed Signal

1. Given Information:
- Number of voice signals = 8
- Each signal is limited to 4 kHz
- Sampled at Nyquist rate
- Quantization levels = 256

2. Calculation of Bandwidth Required:
- Since each voice signal is limited to 4 kHz, the total bandwidth required for all 8 signals = 8 * 4 kHz = 32 kHz

3. Calculation of Bit Depth:
- With 256 quantization levels, the number of bits required to represent each sample = log2(256) = 8 bits

4. Calculation of Bit Rate:
- The bit rate for a single voice signal = 4 kHz * 8 bits = 32 kbps
- Total bit rate for all 8 signals = 8 * 32 kbps = 256 kbps

5. Calculation of Time-Division Multiplexed Signal:
- In time-division multiplexing, each signal is allotted a specific time slot
- Since there are 8 signals, each signal will be allotted 1/8th of the time
- The total bit rate for the time-division multiplexed signal = 8 * 256 kbps = 512 kbps

Therefore, the bit transmission rate for the time-division multiplexed signal will be 512 kbps.
< Previous Question Next Question >
Explore Courses for GATE exam

Similar GATE Doubts

Consider a simple communication system where multiple nodes are connected by a shared broadcast medium (like Ethernet or wireless). The nodes in the system use the following carrier-sense based medium access protocol. A node that receives a packet to transmit will carrier-sense the medium for 5 units of time. If the node does not detect any other transmission in this duration, it starts transmitting its packet in the next time unit. If the node detects another transmission, it waits until this other transmission finishes, and then begins to carrier-sense for 5 time units again. Once they start to transmit, nodes do not perform any collision detection and continue transmission even if a collision occurs. All transmissions last for 20 units of time. Assume that the transmission signal travels at the speed of 10 meters per unit time in the medium.Assume that the system has two nodes P and Q, located at a distance d meters from each other. P starts transmitting a packet at time t=0 after successfully completing its carrier-sense phase. Node Q has a packet to transmit at time t=0 and begins to carrier-sense the medium. The maximum distance d (in meters, rounded to the closest integer) that allows Q to successfully avoid a collision between its proposed transmission and P’s ongoing transmission is _____. Correct answer is '50 to 50'. Can you explain this answer?

Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer?
Question Description
Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer?.
Solutions for Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer?, a detailed solution for Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? has been provided alongside types of Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Eight voice signals, each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be (in kbps)____Correct answer is '512'. Can you explain this answer? tests, examples and also practice GATE tests.
Explore Courses for GATE exam

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup