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The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, then the least count of the microscope is
  • a)
    0.02 mm
  • b)
    0.05 mm
  • c)
    0.01 mm
  • d)
    0.1 mm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The vernier scale of a travelling microscope has 50 divisions which co...
1 MSD = 0.5mm
50VSD = 49MSD
1 VSD = 49/50 MSD
Least Count = 1 MSD - 1 VSD
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Most Upvoted Answer
The vernier scale of a travelling microscope has 50 divisions which co...
Given,

Number of main scale divisions = 49
Number of vernier scale divisions = 50

We know that the least count of a travelling microscope is given by:

Least count = (1 main scale division)/ (number of divisions on the vernier scale)

Here,

1 main scale division = 0.5 mm (given)
Number of divisions on the vernier scale = 50

Substituting the values in the above equation, we get:

Least count = 0.5 mm/50

Least count = 0.01 mm

Therefore, the least count of the microscope is 0.01 mm, which is option (C).
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The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, then the least count of the microscope isa)0.02 mmb)0.05 mmc)0.01 mmd)0.1 mmCorrect answer is option 'C'. Can you explain this answer?
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