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The 9th division of vernier scale coincides with 6th division of main scale in a vernier calliper. If one main scale division is 0.01 mm, then the least count of instrument is
- a)0.01 mm
- b)0.001 mm
- c)0.0033 mm
- d)0.0066 mm
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The 9th division of vernier scale coincides with 6th division of main...
9 VSD = 6 MSD
and L.C. = 1 MSD - 1 VSD
= 0.01/3 mm = 0.0033 mm
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The 9th division of vernier scale coincides with 6th division of main...
Given:
- The 9th division of the vernier scale coincides with the 6th division of the main scale in a vernier caliper.
- One main scale division is 0.01 mm.
To find:
The least count of the instrument.
Solution:
The least count of an instrument is the smallest measurement that can be measured using the instrument. It is determined by the number of divisions on the main scale and the vernier scale.
Main Scale:
- The main scale is the fixed scale of the vernier caliper.
- Each division on the main scale is equal to 1 main scale division.
- Given that one main scale division is 0.01 mm.
Vernier Scale:
- The vernier scale is the movable scale of the vernier caliper.
- It is divided into a certain number of divisions that are slightly smaller than the main scale divisions.
- The vernier scale moves along with the main scale to measure the length of an object.
- The position of the zero mark on the vernier scale determines the reading on the main scale.
Condition:
- The 9th division of the vernier scale coincides with the 6th division of the main scale.
Analysis:
- The vernier scale has 9 divisions.
- The main scale has 6 divisions.
Calculation:
- To calculate the least count, we need to find the difference between one main scale division and one vernier scale division.
- The difference between the two coinciding divisions is given by:
Difference = Value of one main scale division - Value of one vernier scale division
- Since the 9th division of the vernier scale coincides with the 6th division of the main scale, the value of one vernier scale division is:
Value of one vernier scale division = 6 * Value of one main scale division
= 6 * 0.01 mm
= 0.06 mm
- Therefore, the least count of the instrument is equal to the value of one vernier scale division, which is 0.06 mm.
Conclusion:
- The least count of the instrument is 0.06 mm.
- Thus, the correct answer is option C) 0.0033 mm.
- The 9th division of the vernier scale coincides with the 6th division of the main scale in a vernier caliper.
- One main scale division is 0.01 mm.
To find:
The least count of the instrument.
Solution:
The least count of an instrument is the smallest measurement that can be measured using the instrument. It is determined by the number of divisions on the main scale and the vernier scale.
Main Scale:
- The main scale is the fixed scale of the vernier caliper.
- Each division on the main scale is equal to 1 main scale division.
- Given that one main scale division is 0.01 mm.
Vernier Scale:
- The vernier scale is the movable scale of the vernier caliper.
- It is divided into a certain number of divisions that are slightly smaller than the main scale divisions.
- The vernier scale moves along with the main scale to measure the length of an object.
- The position of the zero mark on the vernier scale determines the reading on the main scale.
Condition:
- The 9th division of the vernier scale coincides with the 6th division of the main scale.
Analysis:
- The vernier scale has 9 divisions.
- The main scale has 6 divisions.
Calculation:
- To calculate the least count, we need to find the difference between one main scale division and one vernier scale division.
- The difference between the two coinciding divisions is given by:
Difference = Value of one main scale division - Value of one vernier scale division
- Since the 9th division of the vernier scale coincides with the 6th division of the main scale, the value of one vernier scale division is:
Value of one vernier scale division = 6 * Value of one main scale division
= 6 * 0.01 mm
= 0.06 mm
- Therefore, the least count of the instrument is equal to the value of one vernier scale division, which is 0.06 mm.
Conclusion:
- The least count of the instrument is 0.06 mm.
- Thus, the correct answer is option C) 0.0033 mm.
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The 9th division of vernier scale coincides with 6th division of main scale in a vernier calliper. If one main scale division is 0.01 mm, then the least count of instrument isa)0.01 mmb)0.001 mmc)0.0033 mmd)0.0066 mmCorrect answer is option 'C'. Can you explain this answer?
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The 9th division of vernier scale coincides with 6th division of main scale in a vernier calliper. If one main scale division is 0.01 mm, then the least count of instrument isa)0.01 mmb)0.001 mmc)0.0033 mmd)0.0066 mmCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The 9th division of vernier scale coincides with 6th division of main scale in a vernier calliper. If one main scale division is 0.01 mm, then the least count of instrument isa)0.01 mmb)0.001 mmc)0.0033 mmd)0.0066 mmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The 9th division of vernier scale coincides with 6th division of main scale in a vernier calliper. If one main scale division is 0.01 mm, then the least count of instrument isa)0.01 mmb)0.001 mmc)0.0033 mmd)0.0066 mmCorrect answer is option 'C'. Can you explain this answer?.
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