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10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?
- a)6 g mol−1
- b)60 g mol−1
- c)36 g mol−1
- d)32 g mol−1
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
10% solution of urea is isotonic with 6% solution of a non-volatile so...
No. of moles of urea = 10/60 = 16
Weight of solute, X = 6 g
No. of moles of X = 6/M
For isotonic solutions, n1 = n2
or 1/6 = 6/M or M = 36 g mol−1
Weight of solute, X = 6 g
No. of moles of X = 6/M
For isotonic solutions, n1 = n2
or 1/6 = 6/M or M = 36 g mol−1
Most Upvoted Answer
10% solution of urea is isotonic with 6% solution of a non-volatile so...
The concept of isotonicity is based on the number of particles present in a solution, rather than the mass or molecular weight of the solute.
In this case, we know that a 10% solution of urea is isotonic with a 6% solution of solute X. This means that both solutions have the same osmotic pressure and therefore the same number of particles per unit volume.
Since urea is a small molecule and non-volatile, we can assume that it dissociates into one particle in solution. Therefore, a 10% solution of urea contains 10 g of urea per 100 mL, which corresponds to 10/60 = 1/6 moles of urea per 100 mL.
For the 6% solution of solute X to be isotonic with the urea solution, it must also contain the same number of particles per unit volume. Since we don't know the molecular weight or formula of solute X, we can't directly calculate its molecular mass. However, we can use the relationship between concentration and moles to determine the number of moles of solute X in the 6% solution.
A 6% solution contains 6 g of solute X per 100 mL, which corresponds to 6/100 = 3/50 moles of solute X per 100 mL.
Since the urea solution and the solute X solution are isotonic, they contain the same number of particles per unit volume. Therefore, the number of moles of solute X per 100 mL must be equal to 1/6.
Setting up the equation:
3/50 = 1/6
Cross-multiplying:
18 = 50
This equation is not true, so it seems that there has been an error in the question or calculations. The molecular mass of solute X cannot be determined with the given information.
In this case, we know that a 10% solution of urea is isotonic with a 6% solution of solute X. This means that both solutions have the same osmotic pressure and therefore the same number of particles per unit volume.
Since urea is a small molecule and non-volatile, we can assume that it dissociates into one particle in solution. Therefore, a 10% solution of urea contains 10 g of urea per 100 mL, which corresponds to 10/60 = 1/6 moles of urea per 100 mL.
For the 6% solution of solute X to be isotonic with the urea solution, it must also contain the same number of particles per unit volume. Since we don't know the molecular weight or formula of solute X, we can't directly calculate its molecular mass. However, we can use the relationship between concentration and moles to determine the number of moles of solute X in the 6% solution.
A 6% solution contains 6 g of solute X per 100 mL, which corresponds to 6/100 = 3/50 moles of solute X per 100 mL.
Since the urea solution and the solute X solution are isotonic, they contain the same number of particles per unit volume. Therefore, the number of moles of solute X per 100 mL must be equal to 1/6.
Setting up the equation:
3/50 = 1/6
Cross-multiplying:
18 = 50
This equation is not true, so it seems that there has been an error in the question or calculations. The molecular mass of solute X cannot be determined with the given information.
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10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer?
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10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer?.
10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?a)6 g mol−1b)60 g mol−1c)36 g mol−1d)32 g mol−1Correct answer is option 'C'. Can you explain this answer?.
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