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H2S is a toxic gas used in qualitative analysis. If solubility of H2S in water at STPSTP is 0.195m, what is the value of KH?
  • a)
    0.0263 bar
  • b)
    69.16 bar
  • c)
    192 bar
  • d)
    282 bar
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
H2S is a toxic gas used in qualitative analysis. If solubility of H2S ...
No. of moles of H2S = 0.195
No. of moles of H2O = 1000/18 = 55.55mol
Mole fraction of H2S =
Pressure at STP = 0.987 bar
According to Henry’s law, p = KHx
or KH = pH2S/xH2S = 0.98/70.0035
= 282 bar
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Most Upvoted Answer
H2S is a toxic gas used in qualitative analysis. If solubility of H2S ...
Solution:

The solubility of H2S gas in water at STP is given as 0.195 M.

The Henry's law constant (KH) for H2S gas can be calculated using the formula:

KH = pressure of H2S gas / concentration of H2S gas in solution

At STP, the pressure of H2S gas is equal to its partial pressure, which can be calculated using the ideal gas law:

PV = nRT

where P is the partial pressure of H2S gas, V is the volume of the gas, n is the number of moles of the gas, R is the gas constant, and T is the temperature.

At STP, the volume of 1 mole of any gas is 22.4 L. Therefore, for H2S gas, the volume V = nRT/P = (1 mol)(0.0821 L atm mol^-1 K^-1)(273 K)/(1 atm) = 22.4 L.

The number of moles of H2S gas can be calculated using its solubility in water:

0.195 mol/L x 1 L = 0.195 mol

Therefore, the partial pressure of H2S gas is:

P = nRT/V = (0.195 mol)(0.0821 L atm mol^-1 K^-1)(273 K)/(22.4 L) = 2.41 atm

Finally, the Henry's law constant can be calculated using the formula:

KH = pressure of H2S gas / concentration of H2S gas in solution = (2.41 atm) / (0.195 M) = 282 bar

Therefore, the correct answer is option D, 282 bar.
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H2S is a toxic gas used in qualitative analysis. If solubility of H2S in water at STPSTP is 0.195m, what is the value of KH?a)0.0263 barb)69.16 barc)192 bard)282 barCorrect answer is option 'D'. Can you explain this answer?
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