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When a current of 2A flows in a battery from negative to positive terminal, the potential difference across it is 12V. If a current of 3A flowing in the opposite direction produces a potential difference of 15V, the emf of the battery is
- a)12.6V
- b)13.2V
- c)13.5V
- d)14.0V
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
When a current of 2A flows in a battery from negative to positive term...
Let ε be emf and r be internal resistance of the battery.
In first case,
12 = ε − 2r ...(i)
In second case,
15 = ε + 3r ...(ii)
Subtract (i) from (ii), we get
r = 3 / 5Ω
Putting this value of r in eqn. (i), we get
=
= 66/5 = 13.2V
In first case,
12 = ε − 2r ...(i)
In second case,
15 = ε + 3r ...(ii)
Subtract (i) from (ii), we get
r = 3 / 5Ω
Putting this value of r in eqn. (i), we get
=
= 66/5 = 13.2V
Most Upvoted Answer
When a current of 2A flows in a battery from negative to positive term...
Given:
Current flowing in the battery from negative to positive terminal, I1 = 2A
Potential difference across the battery, V1 = 12V
Current flowing in the battery from positive to negative terminal, I2 = 3A
Potential difference across the battery, V2 = 15V
To find: EMF of the battery
Explanation:
The potential difference across a battery is the difference between the potential at its positive and negative terminals. It is denoted by 'V'.
When a current flows in a battery, it causes a potential difference across the battery. This potential difference is due to the chemical reactions that occur inside the battery. The potential difference across the battery is the energy per unit charge produced by these chemical reactions. It is denoted by 'E'.
The potential difference across the battery due to the presence of a current is given by:
V = E - Ir
Where,
I = Current flowing in the battery
r = Internal resistance of the battery
When the current flows from negative to positive terminal, the potential difference across the battery is given by:
V1 = E - I1r
Similarly, when the current flows from positive to negative terminal, the potential difference across the battery is given by:
V2 = E - I2r
Subtracting these two equations, we get:
V1 - V2 = I1r - I2r
=> V1 - V2 = (I1 - I2)r
=> r = (V1 - V2) / (I1 - I2)
Substituting the given values, we get:
r = (12 - 15) / (2 - 3) = 3Ω
The EMF of the battery is given by:
E = V1 + I1r
Substituting the values of V1, I1, and r, we get:
E = 12 + 2 x 3 = 18V
Therefore, the EMF of the battery is 18V, which is option 'B'.
Current flowing in the battery from negative to positive terminal, I1 = 2A
Potential difference across the battery, V1 = 12V
Current flowing in the battery from positive to negative terminal, I2 = 3A
Potential difference across the battery, V2 = 15V
To find: EMF of the battery
Explanation:
The potential difference across a battery is the difference between the potential at its positive and negative terminals. It is denoted by 'V'.
When a current flows in a battery, it causes a potential difference across the battery. This potential difference is due to the chemical reactions that occur inside the battery. The potential difference across the battery is the energy per unit charge produced by these chemical reactions. It is denoted by 'E'.
The potential difference across the battery due to the presence of a current is given by:
V = E - Ir
Where,
I = Current flowing in the battery
r = Internal resistance of the battery
When the current flows from negative to positive terminal, the potential difference across the battery is given by:
V1 = E - I1r
Similarly, when the current flows from positive to negative terminal, the potential difference across the battery is given by:
V2 = E - I2r
Subtracting these two equations, we get:
V1 - V2 = I1r - I2r
=> V1 - V2 = (I1 - I2)r
=> r = (V1 - V2) / (I1 - I2)
Substituting the given values, we get:
r = (12 - 15) / (2 - 3) = 3Ω
The EMF of the battery is given by:
E = V1 + I1r
Substituting the values of V1, I1, and r, we get:
E = 12 + 2 x 3 = 18V
Therefore, the EMF of the battery is 18V, which is option 'B'.
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When a current of 2A flows in a battery from negative to positive terminal, the potential difference across it is 12V. If a current of 3A flowing in the opposite direction produces a potential difference of 15V, the emf of the battery isa)12.6Vb)13.2Vc)13.5Vd)14.0VCorrect answer is option 'B'. Can you explain this answer?
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When a current of 2A flows in a battery from negative to positive terminal, the potential difference across it is 12V. If a current of 3A flowing in the opposite direction produces a potential difference of 15V, the emf of the battery isa)12.6Vb)13.2Vc)13.5Vd)14.0VCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When a current of 2A flows in a battery from negative to positive terminal, the potential difference across it is 12V. If a current of 3A flowing in the opposite direction produces a potential difference of 15V, the emf of the battery isa)12.6Vb)13.2Vc)13.5Vd)14.0VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a current of 2A flows in a battery from negative to positive terminal, the potential difference across it is 12V. If a current of 3A flowing in the opposite direction produces a potential difference of 15V, the emf of the battery isa)12.6Vb)13.2Vc)13.5Vd)14.0VCorrect answer is option 'B'. Can you explain this answer?.
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