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The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the
  • a)
    Fourth Bohr orbit to the first Bohr orbit 
  • b)
    Fifth Bohr orbit to the second Bohr orbit 
  • c)
    Sixth Bohr orbit to the third Bohr orbit
  • d)
    Seventh Bohr orbit to the third Bohr orbit
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The third line of the Balmer series in the emissionspectrum of the hyd...
Rydberg’s formula for calculation of wavenumbers of hues in hydrogen spectrum is

For Balmer series, n1 = 2 and n2 = 3, 4, 5, so third line of the Balmer series is due to transition from fifth Bohr orbit to second Bohr orbit
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Most Upvoted Answer
The third line of the Balmer series in the emissionspectrum of the hyd...
Explanation:

Balmer Series:
The Balmer series is a set of spectral lines emitted by hydrogen atoms when electrons transition between higher energy levels (orbits) to the second energy level (or orbit). These transitions result in the emission of photons with specific wavelengths.

Third Line of Balmer Series:
The third line of the Balmer series corresponds to the transition from the fifth energy level (or orbit) to the second energy level (or orbit) in the hydrogen atom.

Bohr Model of the Hydrogen Atom:
The Bohr model of the hydrogen atom was proposed by Niels Bohr in 1913. According to this model, electrons in the hydrogen atom occupy specific energy levels or orbits around the nucleus. Each orbit is associated with a specific energy value.

Explanation of the Correct Answer:
The correct answer is option 'B', which states that the third line of the Balmer series is due to the transition from the fifth Bohr orbit to the second Bohr orbit.

Reasoning:
- According to the Bohr model of the hydrogen atom, electrons can transition between different energy levels by absorbing or emitting photons.
- The Balmer series specifically refers to the transitions of electrons from higher energy levels to the second energy level.
- The Balmer series includes several spectral lines, each corresponding to a specific transition.
- The third line of the Balmer series corresponds to the transition from the fifth energy level (or orbit) to the second energy level (or orbit) in the hydrogen atom.
- This transition results in the emission of a photon with a specific wavelength, which corresponds to the third line of the Balmer series.

In Summary:
The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the fifth Bohr orbit to the second Bohr orbit. This transition results in the emission of a photon with a specific wavelength, which corresponds to the third line of the Balmer series.
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The third line of the Balmer series in the emissionspectrum of the hydrogen atom is due to thetransition from thea)Fourth Bohr orbit to the first Bohr orbitb)Fifth Bohr orbit to the second Bohr orbitc)Sixth Bohr orbit to the third Bohr orbitd)Seventh Bohr orbit to the third Bohr orbitCorrect answer is option 'B'. Can you explain this answer?
Question Description
The third line of the Balmer series in the emissionspectrum of the hydrogen atom is due to thetransition from thea)Fourth Bohr orbit to the first Bohr orbitb)Fifth Bohr orbit to the second Bohr orbitc)Sixth Bohr orbit to the third Bohr orbitd)Seventh Bohr orbit to the third Bohr orbitCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The third line of the Balmer series in the emissionspectrum of the hydrogen atom is due to thetransition from thea)Fourth Bohr orbit to the first Bohr orbitb)Fifth Bohr orbit to the second Bohr orbitc)Sixth Bohr orbit to the third Bohr orbitd)Seventh Bohr orbit to the third Bohr orbitCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The third line of the Balmer series in the emissionspectrum of the hydrogen atom is due to thetransition from thea)Fourth Bohr orbit to the first Bohr orbitb)Fifth Bohr orbit to the second Bohr orbitc)Sixth Bohr orbit to the third Bohr orbitd)Seventh Bohr orbit to the third Bohr orbitCorrect answer is option 'B'. Can you explain this answer?.
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