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How many number of aluminium ions are present in 0.051 g of aluminium oxide?
- a)6.023 x 1020 ions
- b)3 ions
- c)6.023 x 1023 ions
- d)9 ions
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
How many number of aluminium ions are present in 0.051 g of aluminium ...
Mass of AI2O3 = 2 x 27 + 3 x 16 = 102
0.051 g of AI2O3 = 0.051/102 = 0.0005 mol
1 mol of AI2O3 contains 2 x 6.023 x 1023 Al3+ ions
0.0005 mol of AI2O3 contains 2 x 0.0005 x 6.023 x 1023
Al3+ ions = 6.023 x 1020 Al3+ ions
0.051 g of AI2O3 = 0.051/102 = 0.0005 mol
1 mol of AI2O3 contains 2 x 6.023 x 1023 Al3+ ions
0.0005 mol of AI2O3 contains 2 x 0.0005 x 6.023 x 1023
Al3+ ions = 6.023 x 1020 Al3+ ions
Most Upvoted Answer
How many number of aluminium ions are present in 0.051 g of aluminium ...
Calculation of Number of Aluminum Ions in Aluminum Oxide
Given:
- Mass of aluminum oxide = 0.051 g
To find:
- Number of aluminum ions present in the given mass of aluminum oxide
Solution:
Step 1: Write the chemical formula of aluminum oxide
Aluminum oxide has the chemical formula Al2O3. It contains two aluminum ions (Al3+) and three oxide ions (O2-).
Step 2: Calculate the molar mass of aluminum oxide
Aluminum has an atomic mass of 26.98 g/mol, and oxygen has an atomic mass of 16.00 g/mol.
Molar mass of Al2O3 = (2 x 26.98 g/mol) + (3 x 16.00 g/mol) = 101.96 g/mol
Step 3: Calculate the number of moles of aluminum oxide
Number of moles of Al2O3 = Mass of Al2O3 / Molar mass of Al2O3
Number of moles of Al2O3 = 0.051 g / 101.96 g/mol = 0.0005 mol
Step 4: Calculate the number of moles of aluminum ions
Since there are two aluminum ions in one molecule of Al2O3, the number of moles of aluminum ions will be twice the number of moles of Al2O3.
Number of moles of Al3+ = 2 x Number of moles of Al2O3 = 2 x 0.0005 mol = 0.001 mol
Step 5: Calculate the number of aluminum ions
Number of aluminum ions = Avogadro's number x Number of moles of Al3+
Number of aluminum ions = 6.023 x 10^23 ions/mol x 0.001 mol = 6.023 x 10^20 ions
Therefore, the number of aluminum ions present in 0.051 g of aluminum oxide is 6.023 x 10^20 ions.
Answer: (a) 6.023 x 10^20 ions
Given:
- Mass of aluminum oxide = 0.051 g
To find:
- Number of aluminum ions present in the given mass of aluminum oxide
Solution:
Step 1: Write the chemical formula of aluminum oxide
Aluminum oxide has the chemical formula Al2O3. It contains two aluminum ions (Al3+) and three oxide ions (O2-).
Step 2: Calculate the molar mass of aluminum oxide
Aluminum has an atomic mass of 26.98 g/mol, and oxygen has an atomic mass of 16.00 g/mol.
Molar mass of Al2O3 = (2 x 26.98 g/mol) + (3 x 16.00 g/mol) = 101.96 g/mol
Step 3: Calculate the number of moles of aluminum oxide
Number of moles of Al2O3 = Mass of Al2O3 / Molar mass of Al2O3
Number of moles of Al2O3 = 0.051 g / 101.96 g/mol = 0.0005 mol
Step 4: Calculate the number of moles of aluminum ions
Since there are two aluminum ions in one molecule of Al2O3, the number of moles of aluminum ions will be twice the number of moles of Al2O3.
Number of moles of Al3+ = 2 x Number of moles of Al2O3 = 2 x 0.0005 mol = 0.001 mol
Step 5: Calculate the number of aluminum ions
Number of aluminum ions = Avogadro's number x Number of moles of Al3+
Number of aluminum ions = 6.023 x 10^23 ions/mol x 0.001 mol = 6.023 x 10^20 ions
Therefore, the number of aluminum ions present in 0.051 g of aluminum oxide is 6.023 x 10^20 ions.
Answer: (a) 6.023 x 10^20 ions
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How many number of aluminium ions are present in 0.051 g of aluminium oxide?a)6.023 x 1020 ionsb)3 ionsc)6.023 x 1023 ionsd)9 ionsCorrect answer is option 'A'. Can you explain this answer?
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