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Nitrogen forms stable N2​ molecule but phosphorus is converted to P4​ from P2​ because:
  • a)
    pπ-pπ bonding is strong in phosphorus
  • b)
    pπ-pπ bonding is weak in phosphorus
  • c)
    Triple bond is present in phosphorus
  • d)
    Single P−P bond is weaker than N−N bond
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Nitrogen forms stableN2molecule but phosphorus is converted toP4fromP2...
pπ - pπ bonding in nitrogen is strong hence it can form triple bond with another N. Single N−N bond is weaker than P−P bond due to high interionic repulsion of non-bonding electrons. Hence, N=N is stable and P2 is not.
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Nitrogen forms stableN2molecule but phosphorus is converted toP4fromP2because:a)pπ-pπbonding is strong in phosphorusb)pπ-pπbonding is weak in phosphorusc)Triple bond is present in phosphorusd)SingleP−Pbond is weaker thanN−NbondCorrect answer is option 'B'. Can you explain this answer?
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Nitrogen forms stableN2molecule but phosphorus is converted toP4fromP2because:a)pπ-pπbonding is strong in phosphorusb)pπ-pπbonding is weak in phosphorusc)Triple bond is present in phosphorusd)SingleP−Pbond is weaker thanN−NbondCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Nitrogen forms stableN2molecule but phosphorus is converted toP4fromP2because:a)pπ-pπbonding is strong in phosphorusb)pπ-pπbonding is weak in phosphorusc)Triple bond is present in phosphorusd)SingleP−Pbond is weaker thanN−NbondCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nitrogen forms stableN2molecule but phosphorus is converted toP4fromP2because:a)pπ-pπbonding is strong in phosphorusb)pπ-pπbonding is weak in phosphorusc)Triple bond is present in phosphorusd)SingleP−Pbond is weaker thanN−NbondCorrect answer is option 'B'. Can you explain this answer?.
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